how to obtain the frequencies from the fft function

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after the fft of the input signal,how to get the frequencies?
  2 Commenti
irem asci
irem asci il 6 Apr 2020
I have 10 seconds of EEG recording that I have used fft on. How can I obtain the frequencies?
numberOfSamples = 20000
samplingRate = 2000
eegFile = readtable('Hit_0_EEG1.txt');
electrodeTimeSeries = eegFile.EEG1;
timeSeries = electrodeTimeSeries(1:numberOfSamples);
y = fft(timeSeries);
posFreq = y(1:(numberOfSamples/2));%
spec = abs(posFreq);
Matan Dor hai
Matan Dor hai il 29 Mag 2022
fs = 2000; % sample rate N = len(your_data); % 20000 in your case fshift = (-N/2:N/2-1)*(fs/N); Y = fftshift(fft(your_data); Y = abs(Y).^2 / N; plot(fshift,Y) % 2 sided fft
fshift = (0:N/2-1)*(fs/N); Yshift = Y(N/2+1:end); plot(fshift,Yshift) % right sided fft

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Wayne King
Wayne King il 30 Set 2013
Modificato: Wayne King il 7 Nov 2013
dpb is correct, you can use that to create a meaningful frequency vector
For an even length signal, the most common interval is (-Fs/2, Fs/2]
Fs = 1000;
t = 0:1/Fs:1-0.001;
x = cos(2*pi*100*t)+randn(size(t));
xdft = fftshift(fft(x));
df = Fs/length(x);
freq = -Fs/2:df:Fs/2-df;
plot(freq,abs(xdft))
For an odd-length signal, it's common to have an open interval (-Fs/2,Fs/2) where the starting point is -Fs/2+ df/2 and the ending point is Fs/2-df/2
Fs = 1000;
t = 0:1/Fs:1;
x = cos(2*pi*100*t)+randn(size(t));
xdft = fftshift(fft(x));
df = Fs/length(x);
half_res = df/2;
freq = -Fs/2+half_res:df:Fs/2-half_res;
plot(freq,abs(xdft))
Of course for a real-valued signal, if you are only interested in magnitude, you only need 1/2 the frequency axis and magnitudes.
If you have the Signal Processing Toolbox, you can use periodogram to get a power spectrum or power spectral density estimate that will output a frequency vector for you.
  1 Commento
Daniel Michael
Daniel Michael il 15 Dic 2022
Are you sure the frequency order is not the following? Not sure why Matlab does not include this in the documentation.
freq = Fs/N*[(0:N/2) -1*((N/2-1):-1:1)]
Unrecognized function or variable 'Fs'.

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Più risposte (6)

dpb
dpb il 30 Set 2013
Frequency is totally dependent upon the sample rate of the time signal and duration.
Sampling relationships --
Fmax=1/2dt; T=Ndt; df=Fmax/(N/2); T=1/df

Daniel Frisch
Daniel Frisch il 12 Nov 2020
easyFFT is not part of Matlab itself, but you have to download it and put the path where it is located to Matlab's path, for example using the addpath() function.
I also helped you with PCA. You have to differentiate between the PCA vector (coeff) in the 3D multivariate space, and the time signals in x,y,z data(:,2:4) or the time signals in the PCA base system, score.
addpath('path/to/folder/of/easyFFT.m')
% Generate random data
L = 1000;
Fs = 5000;
t = (1:L)'/Fs;
f = 200;
data = [ t, sin(2*pi*f*t), cos(2*pi*f*t), t*0];
data(:,2:4) = data(:,2:4) + randn(size(data(:,2:4)))*.1; % add some noise
% Extract data
t = data(:,1);
L = size(data,1);
Accel = data(:,2:4);
% Perform PCA
[coeff,score,latent] = pca(Accel); % need to identify the dominant tremor axis of the 3D accelerometer
% Plot multivariate data in 3D
figure()
plot3([zeros(1,3);(coeff(:,1).*sqrt(latent))'], [zeros(1,3);(coeff(:,2).*sqrt(latent))'], [zeros(1,3);(coeff(:,3).*sqrt(latent))'], 'DisplayName','PCA Base')
hold on
scatter3(data(:,2), data(:,3), data(:,4), 'DisplayName','Data')
axis equal
xlabel('x'), ylabel('y'), zlabel('z')
legend;
% Plot time data, separate for each PCA axes
figure();
plot(t,score, 'DisplayName','Accel along PCA axes');
% 1D Time signal along most dominant tremor axis
score1 = score(:,1); % extract signal projected on most dominant tremor axis coef(:,1)
[Y,f] = easyFFT( score1, length(score1), 1, Fs );
figure();
plot(f, abs(Y), 'DisplayName','Dominant Tremor FFT');
  7 Commenti
Daniel Frisch
Daniel Frisch il 13 Nov 2020
I'm not sure, maybe download easyFFT again, make sure you use Matlab R2020b, and otherwise send me a working example to daniel.frisch\at\posteo.de.
KR
KR il 15 Nov 2020
Thanks, Daniel. Re-downloading easyFFT resolved the issue. Thanks again for all of your help!

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Daniel Frisch
Daniel Frisch il 31 Ago 2020
You can use my little tool easyFFT. It automatically calculates the frequency vector in addition to the FFT.
  2 Commenti
KR
KR il 12 Nov 2020
Hi Daniel,
Do you mind identifying my error in using your easyFFT function? Please note that I need to perform the easyFFT on the first component derived from pca (which I haven't been able to work yet).
data = table2array(acceler);
t = data(:,1);
L = size(data,1);
Accel = data(:,2);
Fs = 5000;
Fn = Fs/2;
coeff = pca(Accel); %need to identify the dominant tremor axis of the 3D accelerometer
figure()
plot(pca(Accel))
legend({'X';'Y';'Z'})
[Y,f] = easyFFT(Accel); %error states 'undefined function or variable 'easyFFT'
Daniel Frisch
Daniel Frisch il 13 Ott 2021
Hi, the "undefined function or variable" error means that the function is not on the path. Either put the file easyFFT.m in your current folder, or add the folder containing it via the addpath() function.

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Jiahaw Fu
Jiahaw Fu il 12 Ott 2021

Mark Newman
Mark Newman il 16 Mag 2022
The FFT gives you a list of results. Each item in the list represents a sinusoid with a different frequency. The position of each item in the list tells you its frequency. See the following video for more details: https://www.youtube.com/watch?v=3aOaUv3s8RY

Dan
Dan il 26 Set 2025
Modificato: Dan il 26 Set 2025
here's a simple wrapper that might help (here dim refers to the matrix dimension to loop the 1-D FFT over):
function [X, f] = run_fft(x, dt, dim, shiftSwitch)
if nargin < 3 || isempty(dim), dim = 2 ; end
if nargin < 4 || isempty(shiftSwitch), shiftSwitch = false ; end
N = size(x, dim) ;
if dim == 1
n = size(x, 2) ;
else
n = size(x, 1) ;
end
NFFT = 2 ^ nextpow2(n) ; % for zero-padding
f = (1 / dt) * (-NFFT / 2 : NFFT / 2 - 1) / NFFT ; % f = 1 / (2 * dt) * linspace(0, 1, NFFT/2 + 1) ; % f = (0 : 1 : N - 1) * fs / N ; % fk = k fs / N where k=0,1,2,...N-1 --- % Map the frequency bin to the frequency (Hz)
if dim == 2, f = f( : ) ; end
if dim == 2, X = zeros(NFFT, N) ; else X = zeros(N, NFFT) ; end
for kx = 1 : N
if dim == 1
xk = x(kx, :) ;
else
xk = x(:, kx) ;
end
nank = isnan(xk) ;
xk(nank) = 0 ; % turn nan's into zeros for zero-padding
Xk = fft(xk, NFFT) ;
if shiftSwitch
Xk = fftshift(Xk) ;
else
f = fftshift( f ) ;
end
if dim == 1
X(kx, :) = Xk ;
else
X(:, kx) = Xk ;
end
end

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