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Questa domanda è chiusa. Riaprila per modificarla o per rispondere.

Can someone help me to implement this algorithm I have tried to but get errors

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Algorithm
Last code = 255
Series = First input character
While not end of while
character = next input character
if (series + character in code table)
series = series + character
else
output = code for series
add series and character to code table
series = character
end
end
output = code for series
Here is my code:
a=[39 39 126 126;39 39 126 126;39 39 126 126;39 39 126 126];
[f,g]=size(a);
total = f*g;
count=1;
imgchar= a(:)';
lastcode = 255;
tel = 1;
reeks = imgchar(1,1);
reekstr = num2str(reeks);
for j = 2:total
kodetabel{j}= strcat(' ');
reekskar{j}= strcat(',');
end
for i=2:total
karakter(1,i)=imgchar(1,i);
karstr = num2str(karakter(1,i));
reekskar{i} = strcat([reekstr,' ',karstr]);
waar = 0;
for k=2:total
if reekskar{i}==kodetabel{k}
reeks= reekskar{i};
waar=1;
end
end
if waar==0
output{tel}=reekstr;
kodetabel{i}=reekskar{i};
lastcode = lastcode+1;
kodetabelnr{i}=lastcode;
reeks=karakter(1,i);
tel = tel+1;
end;
end;
output{tel}=reeks;
  2 Commenti
Martin Park
Martin Park il 7 Ott 2013
Error using == Matrix dimensions must agree.
Error in lzw (line 29) if reekskar{i}==kodetabel{k}

Risposte (2)

Laurent
Laurent il 7 Ott 2013
It depends a bit on what result you want, but if you change that line to
if strcmp(reekskar{i},kodetabel{k})
the script runs. I don't know if this what you want, but at least there is a result. If you want something else, please tell us the result that you expect.
  3 Commenti
Martin Park
Martin Park il 7 Ott 2013
series in my code is named reeks and character is named karakter and code table is kode tabel

Martin Park
Martin Park il 7 Ott 2013
Can anyone help me please

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