vpa(factorial(27)) = 10888869450418351940239884288
...
no trailing zeros
factorial(27) = 1.088886945041835e+28
...
vpa(factorial(27)) - 1.088886945041835e+28 - 2.199023255552000e+12 = 0
I don't get it.
if vpa(factorial) = 10888869450418351940239884288
then there are no trailing zeros...
vpa(factorial(11)) = 39916800
two trailing, like in your problem statement...
am I crazy?
Highphi, any factorial equal to or greater than 5! has to have trailing zeros because it will have one or more pairs of 2 and 5 in its factors. I think factorial(vpa(27)) will give the correct value.
136 Solvers
Reverse the Words (not letters) of a String
298 Solvers
374 Solvers
Change the sign of even index entries of the reversed vector
305 Solvers
729 Solvers
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!