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Jonathan George


Last seen: oltre un anno fa Attivo dal 2022

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Domanda


Finding the generator matrix for x^3+x+1
Hello, I'm inexperienced with MATHLAB and just trying to handle the ropes. I have managed to use genpoly=[1 1 0 1]; [parma...

oltre un anno fa | 1 risposta | 0

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risposta

Domanda


Filter Design using FIR method question
I'm aware that the window method of FIR filter design samples the time-domain function obtained when an inverse Fourier transfor...

quasi 2 anni fa | 1 risposta | 0

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risposta

Domanda


Synthesizing signal given expression
Would would one go about synthesizing a discrete representation of a signal given by the expression x(t)=9cos(421t + 1.99) for 0...

quasi 2 anni fa | 1 risposta | 0

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risposta

Domanda


Transfer function to pole zero diagram
Is there any way to represent a discrete-domain transfer function [H(z)] with a pole zero diagram in MATLAB? And perhaps even vi...

circa 2 anni fa | 1 risposta | 0

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Domanda


A sinusoid has just been fed into a system.
The system in question has a frequency response given by H(w) = 1/(1+0004jw), where w represents frequency in rads/second. Th...

circa 2 anni fa | 2 risposte | 0

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risposte

Domanda


Designing a discrete signal with cutoff frequencies
How would I go about designing a 4th order band stop discrete filter that is designed to filter signals sampled at 10Hz and with...

circa 2 anni fa | 1 risposta | 0

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risposta

Domanda


Synthesising a different kind of discrete signal
How would you go about synthesising a discrete signal given by the expression x[n]=9cos(1.7nT+3.74) for 0<=n<=1654, when the sam...

circa 2 anni fa | 1 risposta | 0

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risposta

Domanda


Designing a specific low-pass discrete filter in MATLAB
How would I go about designing a 6th order low pass discrete filter with a 3dB frequency of 12Hz using the FIR (fir1) window app...

circa 2 anni fa | 1 risposta | 0

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risposta

Domanda


How to synthesise discrete signal?
How can I synthesise a discrete signal given by the expression x[n]=1.23^(-n) for 0<=n<=819? Thank you in advance.

circa 2 anni fa | 2 risposte | 0

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