Steven Gangano
Followers: 0 Following: 0
Statistica
7 Domande
0 Risposte
RANK
200.245
of 292.815
REPUTAZIONE
0
CONTRIBUTI
7 Domande
0 Risposte
ACCETTAZIONE DELLE RISPOSTE
28.57%
VOTI RICEVUTI
0
RANK
of 148.001
CONTRIBUTI
0 Problemi
0 Soluzioni
PUNTEGGIO
0
NUMERO DI BADGE
0
CONTRIBUTI
0 Post
CONTRIBUTI
0 Pubblico Canali
VALUTAZIONE MEDIA
CONTRIBUTI
0 Punti principali
NUMERO MEDIO DI LIKE
Feeds
Domanda
How do I create a nested for loop to find consecutive numbers in a matrix? See example below.
A = [0 1 0 0 1 0 0 1 0 0 0 0 1 0 1 0 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 0 0 1 ...
circa 2 anni fa | 1 risposta | 0
1
rispostaDomanda
Given a matrix, how can I slice a matrix given the input parameters are the number of rows and number of columns? See example.
function [result3Dmatrix] = imgCut(origImgMatrix, numRows, numCols ) For example if matrix is origImgMatrix = [2 4 6 8 ...
oltre 2 anni fa | 1 risposta | 0
1
rispostaDomanda
How do I crop out a certain part within a matrix of numbers?
This example is a small matrix, but I would like to crop out part of this matrix. The part I want to crop out is: a(2,3:5) and ...
oltre 2 anni fa | 1 risposta | 0
1
rispostaDomanda
I have 2 columns in a matrix. 1st column has the dates. 2nd column has the values. How do I grab all values from 2nd column associated with its date from the 1st column??
I have a much larger data set, but this is just a smaller sample size example of what I would like to do. I want to grab all va...
oltre 2 anni fa | 3 risposte | 0
3
risposteDomanda
How do I double the size of a given matrix?
A = [ 1 2 3 4 ] I want to double the size of matrix A by adding a duplicate of row 1 underneath it. And also ad...
oltre 2 anni fa | 1 risposta | 0
1
rispostaDomanda
A(I): index out of bounds; value 6 out of bound 5. How to fix this error?
%I'm trying to subtract the 2nd element from the 1st element %The answer should be: 4-2=2, 6-4=2, 8-6=2, 10-8=2 a = [2:2:10];...
oltre 2 anni fa | 1 risposta | 0
1
rispostaDomanda
How to access the 3rd element in a for loop?
investment = 1000; interestRate = 0.01; months =[1:12]; for month = months investment = investment * (1 + interestRate);...
oltre 2 anni fa | 2 risposte | 0