photo

hosein Javan


Last seen: circa 4 anni fa Attivo dal 2016

Followers: 0   Following: 0

Statistica

All
  • Thankful Level 2
  • Solver
  • Knowledgeable Level 4
  • Thankful Level 1
  • First Answer

Visualizza badge

Feeds

Visto da

Risposto
Modify value of DC voltage source during a simulation
use "controlled voltage source" instead of DC voltage source. connect your look up table to it and it will do it.

circa 4 anni fa | 1

Risposto
Solving differential equation in simulink
hello again. this should look like this: by clicking on "Tune" an app opens and tries to first linearize the system and the...

oltre 4 anni fa | 0

| accettato

Risposto
Find the value x
you can rewrite the equation in the form of "x^(1/x) = exp(1/exp(1))". this means that if "f(z)=z^(1/z)" then we have "f(x) = f(...

oltre 4 anni fa | 2

Domanda


my differential equation general solution form requires very high or low values, exceeding double precision capability, while I know its solution is finite
as a brief explanation, I'm trying to solve a first order bessel equation which is part of a more complicated PDE problem, whose...

oltre 4 anni fa | 0 risposte | 0

0

risposte

Domanda


fastest way to apply A\B on each matrix page
I would like to find an efficient fast way for calculating: for i = 1:n X(:,:,i) = A(:,:,i)\B(:,:,i) end where A and B are 1...

oltre 4 anni fa | 1 risposta | 0

1

risposta

Risposto
negative continuous position on vector
how about: k = find(logical(A)); n = length(A); B = 1-k:n-k A = 0 0 0 0 1 0 0 0 B = ...

oltre 4 anni fa | 1

Risposto
Simulink Electrical Op Amps
your method is correct. this image shows a model that has been tested. what is the problem exactly? any error?

oltre 4 anni fa | 0

Domanda


how to make symbolic computations fast?
hello, I'm working on some calculation that requires great precision at very large or small values. as I have searched the only...

oltre 4 anni fa | 2 risposte | 0

2

risposte

Risposto
Loading a cell array (string) with different lengths into a for loop
you don't even have to concatenate them to one "control" cell array. I suggest create an array called folder where each element ...

oltre 4 anni fa | 0

| accettato

Risposto
index multiple columns together on different critera
A= [0.09 0.48 0.5 0.1 0.04 0.3]; idx1 = A(:,1)<0.2 ; idx2 = A(:,2)>0.2; B(:,1) = A(idx1,1); B(:,2) = A(...

oltre 4 anni fa | 0

Risposto
Concatenate x amount of matrices
after a few (or maybe a lot!) thinking, I found the pattern. I used symbolic to specify each element by its name rather than val...

oltre 4 anni fa | 0

Risposto
How to extract RGB matrices from stacked TIFF file?
not sure. % A = your matrix after reading the image file im = cell(1,n); for i = 1:N im{i} = A(:,:,:,i) % im{i} = indivi...

oltre 4 anni fa | 0

Risposto
A function that outputs multiple plots?
function plotoutput() x = 1:10; y = x.*x; plot(x,y) when you call the function, it shows a figure.

oltre 4 anni fa | 0

| accettato

Risposto
How to create a loop on matrix
for example suppose we want to multiply each column by its coulmn number: A =[ 92 99 1 8 15 67 74 5...

oltre 4 anni fa | 0

| accettato

Risposto
Logarithmic scale with a different base
add the following after plot ax = gca; % current axe ax.XTick = 6:14;

oltre 4 anni fa | 0

Risposto
how can i vary the frequency of the signal
A=240; d=6; x=0:1e-4:1; s=x.^3; a=-(s.*d); minfreq = 10; % minimum frequency(Hz) maxfreq = 200; % maximum frequency(Hz...

oltre 4 anni fa | 0

| accettato

Risposto
sum some values of a column based on an other column
% A is the matrix sized: 8784*2 idx1 = A(:,1)==1; idx2 = A(:,1)==2; idx3 = A(:,1)==3; data = A(:,2); sum(data(idx1)) % ...

oltre 4 anni fa | 1

| accettato

Risposto
How do you set the first column of a 4x4 matrix = a vector
X = [380 250 220 200] C=[1257 679 220 203 1567 155 234 432 2345 445 238 556]; C(1,:)=X; % set the first row of C equ...

oltre 4 anni fa | 0

| accettato

Risposto
no plot appearing for loop
"f" was scalar rather than vector. some constants needed to be defined outside of the loop. and the iteration-depandant variable...

oltre 4 anni fa | 0

Risposto
How to add a noise in my Input graph?
this code gives a zero mean noise with a sampling rate equal to your signal. just calculate it's amplitude by knowing variance. ...

oltre 4 anni fa | 0

| accettato

Risposto
Simulink animation for BLDC motors
I didn't see anything about animate in that video. however I propose after running the simulation, save your data including time...

oltre 4 anni fa | 1

| accettato

Risposto
Computing voltage and current amplitude and average power
if they are 3-phase, use clarke transformation. it will give you the amplitude and phase the dividing by sqrt(2) yield the rms v...

oltre 4 anni fa | 0

| accettato

Risposto
Invalid setting for input port dimensions of 'without_statcom/Asynchronous Machine pu Units/Measurements/Demux1'. The dimensions are being set to [-1]. This is not valid because the total number of input and output elements are not the same
hello. you need to set number of elments in Demux1 correctly. when you run simulation look at the input signal it says for examp...

oltre 4 anni fa | 0

Risposto
plot error variables not same length
try this if could resolve the problem. I have selected those elemnts of "y_fft" corresponding to "f" vector. plot(f, y_fft(1:le...

oltre 4 anni fa | 0

| accettato

Risposto
i have a syntax error in u(3)-u(4)(exp((u(2)u(1)+u(6))))/(u(5))-1) what the error ?
you didn't have product sign"*". also there were bunch of incorrect parantheis. copy and paste should work. u(3)-u(4)*(exp(u(2)...

oltre 4 anni fa | 0

Risposto
Image processing: transition between two halves of an image
you must define the dim factor in a way that is 1.between 0 and 1, 2. it has smooth transition. for example here in order t...

oltre 4 anni fa | 0

| accettato

Risposto
vectors problem, como podria unir los vectores
hola, es esto lo que esperas? A = [1 0 0 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 0 1 0 0]; B = [2 0 2 2 2 0 2 0 2 2 0 0 2 0 2 2 0 0 0 ...

oltre 4 anni fa | 0

| accettato

Risposto
ASSISTANCE ON RUNNING RANDOM VARIABLES IN A FUNCTION
I assumed that "y" must not be a constant since you have dy/dt. therefore I made it an input for the function % define your con...

oltre 4 anni fa | 0

| accettato

Risposto
Calculate mean of a matrix columnwise if a condition is met
A = [10 10 10;10 5 5;10 5 5] b = 10 C = b - A C(A>=b) = nan % replace all data out of specified range by nan mean(C,'omitnan...

oltre 4 anni fa | 0

| accettato

Carica altro