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Clear all fields of a struct

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Karl
Karl il 26 Mar 2014
Commentato: Azzi Abdelmalek il 26 Mar 2014
Hi,
I have a struct with a number of fields that I want populate, and then store, each iteration through a loop. I want the struct to be empty and available each iteration. Is there a function to clear all the fields? Or do I just declare the whole thing again?
I tried setting each feild individually to [], like
myStruct.a = [];
myStruct.b = [];
But it's actually faster to declare the whole thing new each iteration, as in:
myStruct = struct('a', [], 'b', []);
Or maybe there's a better approach all together?
Cheers, Karl

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Karl
Karl il 26 Mar 2014
A colleague suggested this:
myStruct = structfun(@(x) [], myStruct, 'UniformOutput', false);
It's about the same speed-wise, maybe a little faster on average. But it's nice and neat :)
  1 Commento
Azzi Abdelmalek
Azzi Abdelmalek il 26 Mar 2014
clearing your variable doesn't make your code faster, maybe you need to pre-allocate
myStruct = structfun(@(x) zeros(1,100), myStruct, 'UniformOutput', false);

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Azzi Abdelmalek
Azzi Abdelmalek il 26 Mar 2014
Modificato: Azzi Abdelmalek il 26 Mar 2014
%example
a.b=1
a.c=2
a.d=3
%----------------
f=fields(a)
for k=1:numel(f)
a.(f{k})=[];
end
  1 Commento
Karl
Karl il 26 Mar 2014
Modificato: Karl il 26 Mar 2014
Thanks for the reply. This approach does work, but it takes more or less the same amount of time as re-declaring the structure.
Surely there's a better way than resortimg to loops?

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