Why isn't my matrix being filled?
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The intention of this funtion is to be able to give an amount of days and populations for Immune, Sick, and Well people and the function should ouput a matrix with the new population values. Sadly, the function only works for the first two days with the following columns being all zeros. Any tips for me? I'm a beginner
function PopAfterT(t,I0,S0,W0)
populations=zeros(3,t)
populations(:,1)=[I0;S0;W0]
I=zeros(1,t)
I(1,1)=I0
S=zeros(1,t)
S(1,1)=S0
W=zeros(1,t)
W(1,1)=W0
for day=(2:t)
populations(1,day)=I(1,(day-1))+(S(1,(day-1))*.12)-(I(1,day-1)*.01)
populations(2,day)=S(1,(day-1))+(W(1,(day-1))*.08)-(S(1,(day-1))*.04)-(S(1,(day-1))*.02)-(S(1,(day-1))*.12)
populations(3,day)=W(1,(day-1))+(W(1,(day-1))*.06)+(S(1,(day-1))*.02)-(W(1,(day-1))*.02)-(W(1,(day-1))*.08)+(I(1,day-1)*.03)
end
2 Commenti
John D'Errico
il 16 Ott 2021
Do you understand that if you do not return a variable from that function, then nothing changes in your workspace?
Risposte (2)
C B
il 16 Ott 2021
Modificato: C B
il 16 Ott 2021
@Coby Juarez Its because you are using old values of I S W but you are not updating them in loop.
Please have a look at below code where i have updated I S W i hope answer is correct.
function populations = PopAfterT(t,I0,S0,W0)
populations=zeros(3,t);
populations(:,1)=[I0;S0;W0];
I=zeros(1,t);
I(1,1)=I0;
S=zeros(1,t);
S(1,1)=S0;
W=zeros(1,t);
W(1,1)=W0;
for day=(2:t)
I(day)=I(1,(day-1))+(S(1,(day-1))*.12)-(I(1,day-1)*.01);
S(day)=S(1,(day-1))+(W(1,(day-1))*.08)-(S(1,(day-1))*.04)-(S(1,(day-1))*.02)-(S(1,(day-1))*.12);
W(day)=W(1,(day-1))+(W(1,(day-1))*.06)+(S(1,(day-1))*.02)-(W(1,(day-1))*.02)-(W(1,(day-1))*.08)+(I(1,day-1)*.03);
populations(1,day)=I(day);
populations(2,day)=S(day);
populations(3,day)=W(day);
end
Output = PopAfterT(10,4,5,6)
Output =
4.0000 4.5600 5.0640 5.5214 5.9402 6.3267 6.6864 7.0238 7.3428 7.6465
5.0000 4.5800 4.2340 3.9494 3.7159 3.5249 3.3693 3.2434 3.1424 3.0623
6.0000 5.9800 5.9692 5.9670 5.9730 5.9866 6.0074 6.0351 6.0693 6.1096
0 Commenti
DGM
il 16 Ott 2021
Modificato: DGM
il 16 Ott 2021
When you define a function, you need to describe its input arguments and output arguments.
This function definition has no inputs and no outputs
function mybeep()
beep
end
This function definition adds two numbers and returns a single result.
function c = addtwonumbers(a,b)
c = a+b;
end
I'm assuming that the output is supposed to be the populations variable, so
function populations = PopAfterT(t,I0,S0,W0)
% ...
end
0 Commenti
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