Growing eye matrix as per the size of eye

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Babu Thomas
Babu Thomas il 2 Giu 2022
Commentato: Babu Thomas il 2 Giu 2022
I have an eye matrix of size eye(3). I need to increase the size of matrix as below so that eye matrix has to repeat 2 times then 3 times. Can anyone help

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Risposta accettata

Chunru
Chunru il 2 Giu 2022
Ran in:
a = tril(repmat(eye(3), [3, 3]))
a = 9×9
1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1

Più risposte (3)

DGM
DGM il 2 Giu 2022
Ran in:
There are a number of ways, but this is what I'd do:
A = toeplitz([1 0 0 1 0 0 1 0 0],[1 0 0 0 0 0 0 0 0])
A = 9×9
1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1
Bruno Luong
Bruno Luong il 2 Giu 2022
Modificato: Bruno Luong il 2 Giu 2022
Ran in:
tril(repmat(eye(3),3))
ans = 9×9
1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1
KSSV
KSSV il 2 Giu 2022
Ran in:
REad about diag
I = diag(repelem(1,1,9))+diag(repelem(1,1,6),-3)+diag(repelem(1,1,3),-6)
I = 9×9
1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1

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