Automatic generation of Legend
36 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Snr Jhay
il 10 Giu 2022
Commentato: Star Strider
il 11 Giu 2022
I have a program which asks users for vectors. These vectors are used to plot graphs based on previous data in the code. The user is able to specific as many numbers as possible and these are plotted. I want to add a legend that can automatically adjust to fit the number of points the user specifies. 'n' is the user specified vector
for n = [1 50 23 9]
ii = 11 +1;
plot(x, u(:,n+1))
xlabel('x(m)')
ylabel('t(s)')
title('Graph of U against x for specified time intervals')
legend (['t = ', num2str(n)])
grid on
hold on
end
0 Commenti
Risposta accettata
Star Strider
il 10 Giu 2022
Specifically here:
plot(x, u(:,n+1), 'DisplayName',sprintf('t = %2d',n))
and remove the legend call within the loop.
Then after the loop, the legend call is simply either:
legend
or:
legend('Location','best')
or something similar.
So the code would be something like this:
figure
hold on
for n = [1 50 23 9]
ii = 11 +1;
plot(x, u(:,n+1), 'DisplayName',sprintf('t = %2d',n))
xlabel('x(m)')
ylabel('t(s)')
title('Graph of U against x for specified time intervals')
grid on
end
hold off
legend('Location','best')
There are likely better ways to code the loop, however since this appears to be a section of larger code, I will leave it as is.
.
6 Commenti
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Legend in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!