how to repeat a loop?
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arian hoseini
il 13 Giu 2022
Commentato: Image Analyst
il 16 Giu 2022
LD = [1 2 0.004 1 0.05i 0 100
1 3 0.0057 2 0.0714i 0 70
3 4 0.005 3 0.0563i 0 80
4 5 0.005 4 0.045i 0 100
5 6 0.0045 5 0.0409i 0 110
2 6 0.0044 6 0.05i 0 90
1 6 0.005 7 0.05i 0 100];
PTR= 150e3/110;
CTR= [240 240 160 240 240 240 160 240 160 240 240 240 240 160];
for i=1:7
% for n=8:14
z(i,1)=(LD(i,3)+LD(i,5))*LD(i,7);
% z(n,1)=(LD(i,3)+LD(i,5))*LD(i,7);
% end
theta = angle(z(i,1));
z = abs(z)
end
% for i= 1:14
% zsz1(1,i) = ((z(i,1))/(cos((theta(i,1)-45)*pi/180))*(CTR(1,i)/PTR));
% end
i need my loop to repeat again i want answers to be exactly like the first seven z(i,1)...thank u
2 Commenti
Risposta accettata
Image Analyst
il 13 Giu 2022
If you simply want to repeat the loop while printing out exactly the same values each time, then do this:
for k = 1 : 2
for i=1:7
z(i,1)=(LD(i,3)+LD(i,5))*LD(i,7);
theta = angle(z(i,1));
z = abs(z)
end
end
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Più risposte (1)
dpb
il 13 Giu 2022
Modificato: dpb
il 13 Giu 2022
While you could, why not just duplicate the array as many times as needed once it's been generated --
z=repmat(z,2,1);
4 Commenti
Image Analyst
il 16 Giu 2022
If you have the left 4 columns of B already, you could just tack on two copies of z:
z = 1:7;
B=[1 2 1 1
2 1 3 2
3 3 4 3
4 4 5 4
5 5 6 5
6 6 2 6
7 6 1 7
8 1 2 1
9 3 1 2
10 4 3 3
11 5 4 4
12 6 5 5
13 2 6 6
14 1 6 7];
z2 = [z(:); z(:)];
B = [B, z2]
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