Azzera filtri
Azzera filtri

my plot is right for one date but not for other

1 visualizzazione (ultimi 30 giorni)
hello, I should programming this curve with these formula and data (they are on curve) but the finall figuare is right for one and not other,
since I write it for complex number I think something is wrong with my code
btw here my code
close all
clc
clear all
x=0:0.01:pi/2;
nR=3.7;
nI=5.4;
n=nR+nI*i;
mR=0.04;
mI=2.4;
m=mR+mI*i;
z=zeros(length(x),4);
for j=1:length(x);
A=cos(x(j));
B=sqrt((n^2)-((sin(x(j))^2)));
C=(n^2)*(cos(x(j)));
D=cos(x(j));
E=sqrt((m^2)-((sin(x(j))^2)));
F=(m^2)*(cos(x(j)));
rTE1(j)=(A-B)/(A+B);
rTM1(j)=(C-B)/(C+B);
rTE2(j)=(D-E)/(D+E);
rTM2(j)=(F-E)/(F+E);
RTE1(j)= ((rTE1(j))^2);
RTM1(j)= ((rTM1(j))^2);
RTE2(j)= ((rTE2(j))^2);
RTM2(j)= ((rTM2(j))^2);
z(j,1)=RTE1(j);
z(j,2)=RTM1(j);
z(j,3)=RTE2(j);
z(j,4)=RTM2(j);
end
t=x*180/pi;
plot(t,z(:,2),t,z(:,1),t,z(:,4),t,z(:,3))

Risposta accettata

Voss
Voss il 17 Giu 2022
You neglected to take the absolute value of ER/E before squaring. (Notice the warning you got that imaginary parts of complex values are ignored when plotting - this tells you the values being plotted were still complex.)
close all
clc
clear all
x=0:0.01:pi/2;
nR=3.7;
nI=5.4;
n=nR+nI*i;
mR=0.04;
mI=2.4;
m=mR+mI*i;
z=zeros(length(x),4);
for j=1:length(x);
A=cos(x(j));
B=sqrt((n^2)-((sin(x(j))^2)));
C=(n^2)*(cos(x(j)));
D=cos(x(j));
E=sqrt((m^2)-((sin(x(j))^2)));
F=(m^2)*(cos(x(j)));
rTE1(j)=(A-B)/(A+B);
rTM1(j)=(C-B)/(C+B);
rTE2(j)=(D-E)/(D+E);
rTM2(j)=(F-E)/(F+E);
% RTE1(j)= ((rTE1(j))^2);
% RTM1(j)= ((rTM1(j))^2);
% RTE2(j)= ((rTE2(j))^2);
% RTM2(j)= ((rTM2(j))^2);
RTE1(j) = abs(rTE1(j))^2;
RTM1(j) = abs(rTM1(j))^2;
RTE2(j) = abs(rTE2(j))^2;
RTM2(j) = abs(rTM2(j))^2;
z(j,1)=RTE1(j);
z(j,2)=RTM1(j);
z(j,3)=RTE2(j);
z(j,4)=RTM2(j);
end
t=x*180/pi;
plot(t,z(:,2),t,z(:,1),t,z(:,4),t,z(:,3))
  3 Commenti
mhya k
mhya k il 17 Giu 2022
oh really thank you. I though it wouldn't make any problems.ty for help

Accedi per commentare.

Più risposte (0)

Prodotti


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by