Azzera filtri
Azzera filtri

shade area between graphs

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Michiel
Michiel il 28 Feb 2015
Commentato: William Rose il 17 Apr 2024
I want to shade the area between these graphs
but this certainly does not do the trick:
fill([t t(end:-1:1)],[y1 y2(end:-1:1)],'y')
I also downloaded and tried "jblill"
but that did not seem to amend the outcome so far
  2 Commenti
Huijian Huang
Huijian Huang il 15 Dic 2017
have you solve this problem at the end? I am also struggling with similar situation
Image Analyst
Image Analyst il 15 Dic 2017
Yes, there were answers below, one of which he accepted though both should work.

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Risposta accettata

Image Analyst
Image Analyst il 28 Feb 2015
Try using fill() instead of area():
x = 1 : 300;
curve1 = log(x);
curve2 = 2*log(x);
plot(x, curve1, 'r', 'LineWidth', 2);
hold on;
plot(x, curve2, 'b', 'LineWidth', 2);
x2 = [x, fliplr(x)];
inBetween = [curve1, fliplr(curve2)];
fill(x2, inBetween, 'g');
  13 Commenti
Jason Thomas
Jason Thomas il 29 Feb 2024
Hoping this post from 9 years ago is still monitored.
I tried the suggestion above, but instead of filling the area green, it just added thin black lines at the upper and lower bounds. What am I missing?
plot(averageFF2W5I(:,2),averageFF2W5I(:,1), 'k', 'LineWidth', 2);
plot(averageFF2W5I(:,2),averageFF2W5I(:,[8 9]), 'k--', 'LineWidth', 2);
fill([averageFF2W5I(:,2), fliplr(averageFF2W5I(:,2))], [averageFF2W5I(:,8), fliplr(averageFF2W5I(:,9))], 'g');
averageFF2W5I(:,2) = Strain Values
averageFF2W5I(:,1) = Stress Sample Mean
averageFF2W5I(:,[8 9]) = 95% Confidence Interval
William Rose
William Rose il 17 Apr 2024
I don't have your array, so I will use analogous data.
x=0:20; y=x.^.5; ci1=0.8*y; ci2=1.2*y;
fill([x, fliplr(x)], [ci1, fliplr(ci2)], 'g', EdgeColor='none');
hold on
plot(x,y, 'k', 'LineWidth', 2)
plot(x,[ci1;ci2], 'k--', 'LineWidth', 2)
I moved fill() before plot(), so that the line in the middle would not get covered by the fill. Alternatively, you could specify a semitransparent fill. I specified no edge for the fill. I added hold on after fill().

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Più risposte (3)

Star Strider
Star Strider il 28 Feb 2015
Modificato: Star Strider il 28 Feb 2015
Try this:
x = linspace(0,10*pi);
y1 = sin(x);
y2 = cos(x);
figure(1)
plot(x, y1)
hold on
plot(x, y2)
patch([x fliplr(x)], [y1 fliplr(y2)], 'g')
hold off
Experiment with your data to get the result you want.
  10 Commenti
Jason Thomas
Jason Thomas il 29 Feb 2024
@Star Strider THANK YOU!
There were several NaN values in the confidence interval. Once I removed those with rmmissing and used your code with "flip" instead of "fliplr" it worked perfectly.
Star Strider
Star Strider il 29 Feb 2024
My pleasure!
A Vote would be appreciated!

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Javier Montalt Tordera
Javier Montalt Tordera il 12 Apr 2019
This can be simplified using the function shade (in MATLAB File Exchange).
The syntax for the above problem would be:
shade(t,y1,t,y2,'FillType',[1 2;2 1]);
The FillType option specifies that the area between lines 1 and 2 should be filled, whether 1 is above 2 or the other way round.
  5 Commenti
Image Analyst
Image Analyst il 19 Mag 2022
@Giacomo Giuliani, yes though to not cover the line plots you might plot (or re-plot) the line plots after you've plotted the patches between the curves.
Giacomo Giuliani
Giacomo Giuliani il 19 Mag 2022
Modificato: Giacomo Giuliani il 19 Mag 2022
It came to my minds one second after I posted. It works! Thanks.

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Adam Danz
Adam Danz il 29 Gen 2024
Another solution that may be helpful is the fillBetweenAreaCurve function offered by the MATLAB Charting team on the File Exchange.
  1 Commento
Les Beckham
Les Beckham il 29 Feb 2024
FYI - it appears that this File Exchange utility requires the Mapping Toolbox.

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