# Mask with a for loop

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Alexya il 7 Mar 2023
Modificato: Matt J il 7 Mar 2023
I wrote this code that is finding the data i want to remove, i dont know how to mask to remove it from the original vector
vec = [2 3 0 0 7 8 0]
the answer is supposed to be [2 0 0 7 0]
but im getting [3 8], the opposite of what I want, how do i mask to flip this
function [newVec] = removeData(vec)
newVec = [];
for x = 1:length(vec) %don't have to go backwards because we aren't deleting
if vec(x) ~= 0 && vec(x + 1) == 0%checking for not evens
newVec = [newVec vec(x)];
end
end
end
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### Risposte (3)

David Hill il 7 Mar 2023
removeData([2 3 0 0 7 8 0])
ans = 1×5
2 0 0 7 0
function [newVec] = removeData(vec)
newVec = zeros(size(vec));
for x = 1:length(vec) %don't have to go backwards because we aren't deleting
if vec(x) ~= 0 && vec(x + 1) == 0%checking for not evens
newVec(x)=1;
end
end
newVec=vec(~newVec);
end
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Matt J il 7 Mar 2023
Modificato: Matt J il 7 Mar 2023
removeData([2 3 0 0 7 8 0])
ans = 1×5
2 0 0 7 0
function newVec = removeData(vec)
newVec = vec;
newVec( vec(1:end-1) & ~vec(2:end) ) = [];
end
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Voss il 7 Mar 2023
removeData([2 3 0 0 7 8 0])
ans = 1×5
2 0 0 7 0
function vec = removeData(vec)
x = 1;
while x < numel(vec)
if vec(x) ~= 0 && vec(x + 1) == 0%checking for not evens
vec(x) = [];
else
x = x + 1;
end
end
end
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