# How do I create an arithmetic sequence using the counter function, but only using basic mathematics operations (in this case, addition)

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Mpho on 15 Mar 2023
Commented: Fangjun Jiang on 16 Mar 2023
Sq = [2 4 6 8]
N = 3
if (Sq(2) - Sq(1)) == (Sq(end)-Sq(end-1))
d = Sq(2) - Sq(1)
disp("The sequence is arithmetic")
%i would like to use a counter using addition instead of a counter that ranges from values 1 to N. please assist on how to obtain that?
for i = 1:N
Sq(end + 1) = Sq(end)+d;
end
disp(Sq)
end
##### 2 CommentsShow 1 older commentHide 1 older comment
John D'Errico on 15 Mar 2023
Confusing question. Do you want to create a sequence? Or do you want to determine IF a given sequence is arithmetic? The two are very different problems.

Walter Roberson on 15 Mar 2023
Edited: Walter Roberson on 15 Mar 2023
i = 1;
while i <= N
sq(end+1) = sq(end) + d;
i = i + 1;
end
Fangjun Jiang on 16 Mar 2023
N=10;
d=2;
i = 1;
while i <= N
sq(end+1) = sq(end) + d;
i = i + 1;
end
The end operator must be used within an array index expression.
Would mess up the vector length if "sq" was given an initial value
(1:N)*d

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