Azzera filtri
Azzera filtri

Welcome I have a CF equation that performs a three-dimensional summation process and gives a two-dimensional result I did this process using (For Loops) in MATLAB. I want to c

3 visualizzazioni (ultimi 30 giorni)
clc
xm(:,:,1)= [1 2 3 4;2 3 4 5;3 4 5 6;4 5 6 7 ]
xm(:,:,2)= [2 3 4 5;3 4 5 6;4 5 6 7;5 6 7 8]
tic
[cf] =coherence_factor(xm)
toc
function [cf] = coherence_factor(xm)
for i=1:size(xm,1);
for j=1:size(xm,2);
n=size(xm,3);
cf(i,j)=(abs (sum(xm(i,j,:))).^2) / (n* sum(abs(xm(i,j,:).^2)));
end
end
end

Risposta accettata

Dyuman Joshi
Dyuman Joshi il 30 Mar 2023
Modificato: Dyuman Joshi il 30 Mar 2023
%Data
xm(:,:,1)= [1 2 3 4;2 3 4 5;3 4 5 6;4 5 6 7 ];
xm(:,:,2)= [2 3 4 5;3 4 5 6;4 5 6 7;5 6 7 8];
n=size(xm,3);
%Loop Method
for i=1:size(xm,1);
for j=1:size(xm,2);
cf1(i,j)=(abs (sum(xm(i,j,:))).^2) / (n* sum(abs(xm(i,j,:).^2)));
end
end
cf1
cf1 = 4×4
0.9000 0.9615 0.9800 0.9878 0.9615 0.9800 0.9878 0.9918 0.9800 0.9878 0.9918 0.9941 0.9878 0.9918 0.9941 0.9956
%Vectorized method
cf2 = abs(sum(xm,3).^2)./(n*sum(abs(xm.^2),3))
cf2 = 4×4
0.9000 0.9615 0.9800 0.9878 0.9615 0.9800 0.9878 0.9918 0.9800 0.9878 0.9918 0.9941 0.9878 0.9918 0.9941 0.9956

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by