How to arrange alternate cells of a column into two columns?

Let's say the column matrix is:

A =

2

6

7

3

8

3

2

9

7

5

4

1

And I need to obtain final result as

A =

2 6

7 3

8 3

2 9

7 5

4 1

Can I know the way to split in this way?

Answer 1

[Florian Bidaud]

A = [2 6 7 3 8 3 2 9 7 5 4 1]'

A = 12×1

2 6 7 3 8 3 2 9 7 5

B = [A(1:2:end) A(2:2:end)]

B = 6×2

2 6 7 3 8 3 2 9 7 5 4 1

[Dyuman Joshi]

Another option is to use reshape

A = [2 6 7 3 8 3 2 9 7 5 4 1]';
B = reshape(A,2,[])'

B = 6×2

2 6 7 3 8 3 2 9 7 5 4 1

[Manoj Kumar V]

How shall the matrix be formed when there are odd number of elements? Is there a way to make it even by putting zero for the last element? Lets say: A = [2 6 7 3 8 3 2 9 7 5 4]. How can I obtain

B = 6×2

2 6

7 3

8 3

2 9

7 5

4 0

[Dyuman Joshi]

That depends on the size you want to arrange -

%For a 2D array, define atleast one dimension
ncol = 2;

A = [2 6 7 3 8 3 2 9 7 5 4];

%Convert to column vector
A = A(:);

%Add required zeros
A = [A;zeros(1,rem(numel(A),ncol))];

B = reshape(A,ncol,[])'

B = 6×2

2 6 7 3 8 3 2 9 7 5 4 0