Azzera filtri
Azzera filtri

pie chart creation with name (number) and corresponding percentage

17 visualizzazioni (ultimi 30 giorni)
Hi! I would like to create a pie chart like in the present demo:
x = [1,2,3];
p = pie(x);
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
txt = {'Item A: ';'Item B: ';'Item C: '};
combinedtxt = strcat(txt,percentValues);
pText(1).String = combinedtxt(1);
pText(2).String = combinedtxt(2);
pText(3).String = combinedtxt(3);
How can I achieve the same result with my data?
I tried it this way:
number = [78;79;80;81;82;83;84;85;86;87;88]';
value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';
number2 = {};
for K = 1:height(number)
number1 = sprintf('%.0f',number(K));
number2 = [number2,{number1}];
end
number2 = number2.';
p = pie(value);
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
combinedtxt = strcat(number2,percentValues);
for K = 1:height(value)
pText(K).String = combinedtxt(K);
end

Risposta accettata

Star Strider
Star Strider il 30 Ago 2023
Modificato: Star Strider il 30 Ago 2023
One approach —
number = [78;79;80;81;82;83;84;85;86;87;88]';
value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';
f = figure;
p = pie(value);
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
delete(f)
pcts = regexp(percentValues, '\d*', 'match');
pcts = cellfun(@(x)str2double(x), pcts);
idx = pcts<7;
combine = number(idx);
pctv = pcts(idx);
percentVals = compose(' (%d%%)',pcts(~idx));
percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];
nrc = compose('%d ', number(~idx)).';
nrc{end+1} = [num2str(combine) ' '];
cattxt = cellfun(@(x,y)cat(2,x,y),nrc, percentVals, 'Unif',0);
pText(numel(cattxt)+1:end) = [];
value2 = [value(~idx) sum(value(idx))];
figure
p = pie(value2);
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
for k = 1:numel(cattxt)
pText(k).String = cattxt(k);
end
.
  15 Commenti
Star Strider
Star Strider il 4 Set 2023
That may not be possible. I tried my own version, and I don’t get exactly the same results the pie gets, although my calculations otherwise work —
number = [48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88];
value = [0 0 0 0 0 0 42 91 152 276 440 572 821 1155 1580 1761 2157 2256 2578 2499 2715 2794 3280 3237 3263 3586 3334 3652 3675 4404 4509 5239 6400 9074 11047 13147 15137 13909 6354 1152 183];
f = figure;
p = pie(value);
[U_value,nidx,ix] = unique(value,'stable');
Counts = accumarray(ix, value);
sum_Counts = sum(Counts);
Freqs = Counts/sum(Counts) * 100;
[v1,v2] = bounds(Freqs)
v1 = 0
v2 = 11.0917
number_v = number(nidx).';
Interim_Results = table(number_v,Counts,Freqs)
Interim_Results = 36×3 table
number_v Counts Freqs ________ ______ ________ 48 0 0 54 42 0.030776 55 91 0.066681 56 152 0.11138 57 276 0.20224 58 440 0.32241 59 572 0.41914 60 821 0.60159 61 1155 0.84633 62 1580 1.1578 63 1761 1.2904 64 2157 1.5806 65 2256 1.6531 66 2578 1.889 67 2499 1.8312 68 2715 1.9894
Freqs_lt_7 = Freqs < 7; % Threshold Results
Thresholded_Interim_Results_1 = sum(Freqs(Freqs_lt_7))
Thresholded_Interim_Results_1 = 60.9880
Thresholded_Interim_Results_2 = [number_v(~Freqs_lt_7) Freqs(~Freqs_lt_7) round(Freqs(~Freqs_lt_7))];
Thresholded_Interim_Results_2(end+1,:) = [NaN sum(Thresholded_Interim_Results_2(:,2:end))]
Thresholded_Interim_Results_2 = 5×3
82.0000 8.0948 8.0000 83.0000 9.6335 10.0000 84.0000 11.0917 11.0000 85.0000 10.1919 10.0000 NaN 39.0120 39.0000
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
delete(f)
pcts = regexp(percentValues, '\d*', 'match');
pcts = cellfun(@(x)str2double(x), pcts);
idx = pcts<7;
combine = number(idx);
pctv = pcts(idx);
percentVals = compose(' (%d%%)',pcts(~idx));
percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];
nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);
% VARIED
nrc{end+1} = sprintf('%d %d %d %d %d %d (%2d%%)\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d',[combine(1:6) sum(pcts(idx)) combine(7:end)]); % NEW 'nrc{end+1}'
cattxt = nrc;
pText(numel(cattxt)+1:end) = [];
value2 = [value(~idx) sum(value(idx))];
figure
p = pie(value2);
pPatch = findobj(p, 'Type','Patch');
cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
for k = 1:numel(cattxt)
pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually
pText(k).String = []; % Delete The 'String' Labels
end
lgd = legend(cattxt, 'Location','eastoutside','FontSize',12);
.
Voss
Voss il 4 Set 2023
Modificato: Voss il 4 Set 2023
@Alberto Acri: The numbers sum to 107 because the first (deleted) pie chart includes several strings that are "<1%". When you get the number from those strings and use it, of course those are counted as 1 instead of what they really are. The solution is, instead of getting the percentages from a pie chart you're going to delete, just calculate the percentages directly, and they'll have a higher precision. You'll have to round them when you use them in the legend, but here's the important part: the small ones (<1%) do not get "rounded" to 1 and then summed; instead you sum them first and then round the result. You can see below that the total sum is 100:
number = [48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88];
value = [0 0 0 0 0 0 42 91 152 276 440 572 821 1155 1580 1761 2157 2256 2578 2499 2715 2794 3280 3237 3263 3586 3334 3652 3675 4404 4509 5239 6400 9074 11047 13147 15137 13909 6354 1152 183];
% calculate percentages:
pcts = 100*value.'/sum(value);
idx = round(pcts)<7;
combine = number(idx);
pctv = pcts(idx);
nrc = compose('%d (%2d%%)', [number(~idx).', round(pcts(~idx))]);
% VARIED
nrc{end+1} = sprintf('%d %d %d %d %d %d (%2d%%)\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d',[combine(1:6) round(sum(pcts(idx))) combine(7:end)]); % NEW 'nrc{end+1}'
cattxt = nrc;
value2 = [value(~idx) sum(value(idx))];
figure
p = pie(value2);
pPatch = findobj(p, 'Type','Patch');
cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
for k = 1:numel(cattxt)
pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually
pText(k).String = []; % Delete The 'String' Labels
end
lgd = legend(cattxt, 'Location','eastoutside','FontSize',12);

Accedi per commentare.

Più risposte (2)

Benjamin Kraus
Benjamin Kraus il 26 Apr 2024 alle 20:17
It is worth checking out the new (as of R2023b) piechart command.
A new feature (added in R2024a) is the LabelStyle property, which can be used to quickly create the labels you were asking about.
x = [1,2,3];
txt = {'Item A';'Item B';'Item C'};
p = piechart(x, txt);
p.LabelStyle = 'namepercent';

MYBLOG
MYBLOG il 30 Ago 2023
The code you provided is mostly correct, but you can simplify it a bit. Here's how you can achieve the same result with your data:
% Your data
number = [78;79;80;81;82;83;84;85;86;87;88]';
value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';
% Create labels for the pie chart
number2 = cellstr(num2str(number)); % Convert numbers to cell array of strings
% Create the pie chart
p = pie(value);
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
% Combine labels and percentages
combinedtxt = strcat(number2, ': ', percentValues);
% Set the combined text for each slice
for K = 1:numel(value)
pText(K).String = combinedtxt{K};
end

Categorie

Scopri di più su Graphics Object Identification in Help Center e File Exchange

Tag

Prodotti


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by