# contains 函数在运行相同代码时​，为什么返回了不同的​逻辑数组？

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Modificato: Voss il 22 Mag 2024 alle 17:04
a=[ "水果店" "武汉水果店" "宜昌水果店" "襄阳水果店" "荆州水果店"
"饭店" "武汉饭店" "宜昌饭店" "襄阳饭店" "荆州饭店" ];
store_name ={'﻿宜昌水果店','武汉水果店'};
T=contains(a,store_name{1});
T
T = 2x5 logical array
0 0 0 0 0 0 0 0 0 0
store_name ={'宜昌水果店','武汉水果店'};
T=contains(a,store_name{1});
T
T = 2x5 logical array
0 0 1 0 0 0 0 0 0 0
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### Risposta accettata

Voss il 22 Mag 2024 alle 17:03
Modificato: Voss il 22 Mag 2024 alle 17:04
There is a hidden character at the beginning of the first store_name{1}
store_name ={'宜昌水果店','武汉水果店'};
+store_name{1} % character codes
ans = 1x6
65279 23452 26124 27700 26524 24215
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
which is not in the second store_name{1}
store_name ={'宜昌水果店','武汉水果店'};
+store_name{1} % character codes
ans = 1x5
23452 26124 27700 26524 24215
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
There are various ways to remove that extra character, e.g., using strrep:
store_name ={'宜昌水果店','武汉水果店'}; % 1st one again
+store_name{1} % character codes
ans = 1x6
65279 23452 26124 27700 26524 24215
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
store_name{1} = strrep(store_name{1},char(65279),'');
+store_name{1} % character codes
ans = 1x5
23452 26124 27700 26524 24215
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
Now they are the same and produce the same result when checking against a.
a=[ "水果店" "武汉水果店" "宜昌水果店" "襄阳水果店" "荆州水果店"
"饭店" "武汉饭店" "宜昌饭店" "襄阳饭店" "荆州饭店" ];
store_name ={'宜昌水果店','武汉水果店'};
store_name{1} = strrep(store_name{1},char(65279),'');
T = contains(a,store_name{1})
T = 2x5 logical array
0 0 1 0 0 0 0 0 0 0
store_name ={'宜昌水果店','武汉水果店'};
T = contains(a,store_name{1})
T = 2x5 logical array
0 0 1 0 0 0 0 0 0 0
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