
Put arrow and its value in a plot
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Hello there,
I want to show a row and its value in a plot. Please find attached the data. My intended plot should be like this:

load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
Thank you!
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Risposte (3)
Mathieu NOE
il 23 Nov 2024
hello
this is a simple example , based on the fex submission :

load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
% define which row for display
r = 100;
x = PTn(r);
y = z(r);
al = 1; % arrow length (in x direction)
arrow([x-al,y],[x,y]); % Fex : https://fr.mathworks.com/matlabcentral/fileexchange/278-arrow
text(x-4*al, y, ['MLD = ' sprintf('%0.5g', y)])
3 Commenti
Mathieu NOE
il 25 Nov 2024
hello again
try this :

load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
% define which row for display
value = 24.7; % MLD value to display
[x,~] = find_zc(PTn,z,value);
y = value;
al = 1; % arrow length (in x direction)
arrow([x-al,y],[x,y]); % Fex : https://fr.mathworks.com/matlabcentral/fileexchange/278-arrow
text(x-3*al, y, ['MLD = ' sprintf('%0.5g', y)])
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [ZxP,ZxN] = find_zc(x,y,threshold)
% find x values corresponding to y = threshold (like a zero crossing detector) :
% ZxP is x when signal slope is positive at the crossing point
% ZxN is x when signal slope is negative at the crossing point
% put data in rows
x = x(:);
y = y(:);
% positive slope "zero" crossing detection, using linear interpolation
y = y - threshold;
zci = @(data) find(diff(sign(data))>0); %define function: returns indices of +ZCs
ix=zci(y); %find indices of + zero crossings of x
ZeroX = @(x0,y0,x1,y1) x0 - (y0.*(x0 - x1))./(y0 - y1); % Interpolated x value for Zero-Crossing
ZxP = ZeroX(x(ix),y(ix),x(ix+1),y(ix+1));
% negative slope "zero" crossing detection, using linear interpolation
zci = @(data) find(diff(sign(data))<0); %define function: returns indices of +ZCs
ix=zci(y); %find indices of + zero crossings of x
ZeroX = @(x0,y0,x1,y1) x0 - (y0.*(x0 - x1))./(y0 - y1); % Interpolated x value for Zero-Crossing
ZxN = ZeroX(x(ix),y(ix),x(ix+1),y(ix+1));
end
Mathieu NOE
il 25 Nov 2024
and if you need to plot more than one MLD value, you can use this modified code :
NB that I am not using interp1 because your profile is not monotonic everywhere , so interp1 may fail sometimes.

load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
% define which row for display
value = [24.7 33.1 54.7 78.9]; % MLD values to display
al = 1; % arrow length (in x direction)
for k = 1:numel(value)
[x,~] = find_zc(PTn,z,value(k));
x = x(1); % take the first value
arrow([x-al,value(k)],[x,value(k)]); % Fex : https://fr.mathworks.com/matlabcentral/fileexchange/278-arrow
text(x-3*al, value(k), ['MLD = ' sprintf('%0.5g', value(k))])
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [ZxP,ZxN] = find_zc(x,y,threshold)
% find x values corresponding to y = threshold (like a zero crossing detector) :
% ZxP is x when signal slope is positive at the crossing point
% ZxN is x when signal slope is negative at the crossing point
% put data in rows
x = x(:);
y = y(:);
% positive slope "zero" crossing detection, using linear interpolation
y = y - threshold;
zci = @(data) find(diff(sign(data))>0); %define function: returns indices of +ZCs
ix=zci(y); %find indices of + zero crossings of x
ZeroX = @(x0,y0,x1,y1) x0 - (y0.*(x0 - x1))./(y0 - y1); % Interpolated x value for Zero-Crossing
ZxP = ZeroX(x(ix),y(ix),x(ix+1),y(ix+1));
% negative slope "zero" crossing detection, using linear interpolation
zci = @(data) find(diff(sign(data))<0); %define function: returns indices of +ZCs
ix=zci(y); %find indices of + zero crossings of x
ZeroX = @(x0,y0,x1,y1) x0 - (y0.*(x0 - x1))./(y0 - y1); % Interpolated x value for Zero-Crossing
ZxN = ZeroX(x(ix),y(ix),x(ix+1),y(ix+1));
end
Pramil
il 23 Nov 2024
Modificato: Pramil
il 23 Nov 2024
Hi Adi,
You can use the "text" function available in MATLAB to create plot shown in your image. Here is the documentation link for the same for your reference:
And here is the updated code:
load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
[~, idx] = min(abs(z - MLD));
x_value = PTn(idx);
text(x_value, MLD, 'MLD = 24.7\rightarrow ','HorizontalAlignment','right');
Star Strider
il 23 Nov 2024
Modificato: Star Strider
il 23 Nov 2024
The 'textarrow' coordinates have to adapt to the data and then correct for the reversed y-axis direction.
Try this —
load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
xlabel('PTn')
ylabel('z')
xapf = @(x,pos,xl) pos(3)*(x-min(xl))/diff(xl)+pos(1); % 'x' Annotation Position Function
yapf = @(y,pos,yl) pos(4)*(y-min(yl))/diff(yl)+pos(2); % 'y' Annotation Position Function
xl = xlim;
yl = ylim;
pos = gca().Position;
MLDval = 24.7;
PTnval = interp1(z, PTn, MLDval) % X-Coordinate Value (Derived From Data) Right End Of The Arrow
zval = interp1(PTn, z, PTnval) % Y-Coordinate Value (Derived From Data)
annotation('textarrow', xapf(PTnval+[-2.25 -0.25],pos,xl), 1-yapf([1 1]*zval,pos,yl), String=("MLD = "+MLDval)+" m ", HeadStyle='vback3')
EDIT — (23 Nov 2024 at 12:45)
Changed 'HeadStyle'.
.
4 Commenti
Star Strider
il 26 Nov 2024
My pleasure!
It appears that my ‘kludge’ fix is the best option just now. I have not checked to see if it might work in other instances, however I believe it is likely a ‘one-off’ that will not generalise to other situations.
My only consolation is that my code works correctly, and would continue to do so if the absolute references changed with the axis direction (and possibly axis scaling, however I have not experimented with it with a diifferent axiis scale).
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