Strange issue encountered using textscan and cell arrays
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Peter Ryan
il 14 Ott 2016
Commentato: Star Strider
il 14 Ott 2016
When I run the following snippet of code:
str = '(3.3940269999999999,1,0) (0,3.3940269999999999,0) (0,0,2.024902)';
format = '(%f, %d, %d) (%d, %f, %d) (%d, %d, %f)';
A = textscan(str, format);
matrix = [A{1,1}, A{1,4}, A{1,7} ; A{1,2}, A{1,5}, A{1,8}; A{1,3}, A{1,6}, A{1,9}]
I get the following output matrix =
3 0 0
1 3 0
0 0 2
Why were the floating point numbers converted to integers?
0 Commenti
Risposta accettata
Star Strider
il 14 Ott 2016
When I run a slightly modified version of your code (because format is a function that defines the format displayed in the Command Window and Tooltips), I get:
format_string = '(%f, %d, %d) (%d, %f, %d) (%d, %d, %f)';
A = textscan(str, format_string);
matrix =
3×3 int32 matrix
3 0 0
1 3 0
0 0 2
That is likely because of the '%d' format descriptors. Convert them to '%f':
format_string = '(%f, %f, %f) (%f, %f, %f) (%f, %f, %f)';
to get:
matrix =
3.394 0 0
1 3.394 0
0 0 2.0249
3 Commenti
Più risposte (1)
Eamon
il 14 Ott 2016
I think if you use the format function like below before the rest of your code, it will show the original floating point numbers.
format long
Vedere anche
Categorie
Scopri di più su Data Type Conversion in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!