Azzera filtri
Azzera filtri

problem in functin (y for x)

1 visualizzazione (ultimi 30 giorni)
Lila wagou
Lila wagou il 1 Mar 2017
Modificato: Stephen23 il 1 Mar 2017
Hy i have a problem in the flowing code (XZData.m function)
function [x,y] = XZData(A,B,C)
x = 0:1:10;
y = (A*x^2)+(B*x)+C;
XY = ['XData', num2str(x), 'yData', num2str(y)];
disp(XY)

Risposta accettata

Star Strider
Star Strider il 1 Mar 2017
Modificato: Stephen23 il 1 Mar 2017
Use element-wise exponentiation in the ‘y’ assignment:
y = (A*x.^2)+(B*x)+C;
↑ ← INSERT ‘.’ HERE
function [x,y] = XZData(A,B,C)
x = 0:1:10;
y = (A*x.^2)+(B*x)+C;
XY = ['XData ', num2str(x), ' yData ', num2str(y)];
disp(XY)
end
See the documentation on Array vs. Matrix Operations for details.

Più risposte (2)

Walter Roberson
Walter Roberson il 1 Mar 2017
Use x.^2 with the dot instead of x^2

John D'Errico
John D'Errico il 1 Mar 2017
Modificato: John D'Errico il 1 Mar 2017
It makes it easier to get help if you report the (COMPLETE) error message that you got. Help those who would help you.
In this case though, the problem is that you need to learn about the elementwise operators, like .* ./ and .^ , since that is where your immediate problem arises.
Change the computation of y to this:
y = (A*x.^2)+(B*x)+C;
x is a vector. You wish to compute the square of each element of x, so use the .^ operator.
Admittedly, I think your next problem is that you won't like how that line gets displayed in the call to disp. It will be one long line of text. But that is for you to decide.

Categorie

Scopri di più su Creating and Concatenating Matrices in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by