MATLAB Answers

Why is my graph not right?

4 views (last 30 days)
Im trying to make this graph. I was unable to find symbols so I just used numbers for most of the equation (the first one). I need to plot (delta w). Ive added an attachment with the equation and what the graph should look like, if someone could help. This is what I have tried but I keep getting the wrong curve:
>> w0 = 10.^14
w0 =
1.0000e+14
>> y = 5*10.^12
y =
5.0000e+12
>> e3 = 12.1
e3 =
12.1000
>> e4 = 10
e4 =
10
>> w = 50*10.^12:10.^12:150*10.^12;
>> e1 = ((e4)-((e3)-(e4)))*(((2*(w0))*(w))/(((4*((w).^2))+((y).^2))));
>> plot(w,e1)

  0 Comments

Sign in to comment.

Accepted Answer

Star Strider
Star Strider on 19 Dec 2017
Since this was due three weeks ago, I decided to code it myself for fun. There actually seem to be some errors in the homework assignment either in the constants or the range of the independent variable. It may also be that there should be an offset, perhaps something like ‘(dw - w0)’ or some such that would centre the independent variable appropriately to reproduce the plots as posted. (I just experimented with the independent variable until I got the plots to work.)
This produces the plots:
dw = linspace(-25, 25) * 1E+12;
w0 = 1E+14;
gma = 5E+12;
est = 12.1;
einf = 10;
e1 = @(dw) einf - (est - einf)*2*w0*dw./(4*dw.^2 + gma.^2);
e2 = @(dw) (est - einf) * gma*w0./(4*dw.^2 + gma.^2);
n = @(dw) sqrt(e1(dw) + sqrt(e1(dw).^2 + e2(dw).^2))/sqrt(2);
kpa = @(dw) sqrt(-e1(dw) + sqrt(e1(dw).^2 + e2(dw).^2))/sqrt(2);
figure(1)
subplot(2,2,1)
plot(dw, e1(dw))
ylabel('\epsilon_1')
grid
subplot(2,2,3)
plot(dw, e2(dw))
ylabel('\epsilon_2')
xlabel('\omega')
grid
subplot(2,2,2)
plot(dw, n(dw))
ylabel('\it{n}')
grid
subplot(2,2,4)
plot(dw, kpa(dw))
ylabel('\kappa')
xlabel('\omega')
grid
Experiment to get the result you want.

  2 Comments

chris henkel
chris henkel on 19 Dec 2017
thank you, that worked
Star Strider
Star Strider on 19 Dec 2017
My pleasure.

Sign in to comment.

More Answers (0)

Tags


Translated by