Azzera filtri
Azzera filtri

Split variable length vector by parts

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YT
YT il 25 Apr 2018
Modificato: YT il 25 Apr 2018
So it's probably an easy solution, but can't really find the answer that quick.
I have the following vector:
V = [1 2 3 4 5 ... n];
P = ceil(length(V/127)); %dont know if ceil or floor is better
And then I want to split the vector `V` in parts `P`, so that I'll get something like the following:
% as an example n = 2184 & P = 17
C = {[1 2 3 ... 18],[18 19 20 ... 35],...[2167 2168 2169 ...2184]};
Thanks in advance
  1 Commento
Ameer Hamza
Ameer Hamza il 25 Apr 2018
Modificato: Ameer Hamza il 25 Apr 2018
You mentioned that P=17 but your first element of C contain 18 elements. What to do, if elements of V can't be divided properly, e.g. 2184/17 is not an integer. How do you want to handle it?

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dpb
dpb il 25 Apr 2018
L-length(V);
P=17;
id2=[repmat(P,1,fix(L/P)) rem(L,P)]; % number elements in cell size P matching L plus remainder
C=mat2cell(V,1,id2);
That's for the nearest multiple of P with whatever is left over tacked onto the end irregardless of its size relative to P. If it's needed to make as near even as possible need more logic to choose the bin size; that's not a given criterion in the question posed, however.
  1 Commento
YT
YT il 25 Apr 2018
Modificato: YT il 25 Apr 2018
While it works fine and I accepted your answer, I've created a new question related to this one (for more logical sizes of subvectors) >here<

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