Azzera filtri
Azzera filtri

dsolve problem

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Daniel
Daniel il 31 Mag 2012
Hello, I would like to use a function f in a differential equation for example f=x but get a crazy result.
syms x y f
f=x
y=dsolve('D2x=-f','x(0)=1','Dx(0)=0')
How can I put into dsolve a function f defined outside of dsolve?

Risposta accettata

Teja Muppirala
Teja Muppirala il 1 Giu 2012
One way would be to convert f to a string:
syms x y f
f=x
y=dsolve(['D2x=-' char(f)],'x(0)=1','Dx(0)=0')

Più risposte (1)

Walter Roberson
Walter Roberson il 31 Mag 2012
You could try
syms x y f
f=x
eqn1 = subs(sym('D2x=-f'), 'f', f);
y = dsolve(eqn1, 'x(0)=1','Dx(0)=0')
  3 Commenti
Walter Roberson
Walter Roberson il 31 Mag 2012
Ah, I guess it doesn't analyze syms for occurrences of D. Ummm, I will have to make up a variable for x to be related to:
If I read the documentation right,
syms x(t) f(t) t
f = x(t); %or maybe f = x;
D2x = diff(x,2);
Dx = diff(x);
dsolve( D2x == -f, x(0) == 1, Dx(0) == 0 )
Anyhow, the root of the problem is that, as usual, when you have a quoted string like 'D2x=-f', MuPAD does not have access to the value of any variable such as f that was declared at the MATLAB level. subs() is the mechanism to "import" MATLAB-level values to the MuPAD level. It looks like dsolve() interprets symbolic variables differently than it interprets strings so the more obvious subs() does not work. char() around the subs() might perhaps have worked.
Daniel
Daniel il 1 Giu 2012
Thanks for trying.
Teja's code works:
syms x y f
f=x
y=dsolve(['D2x=-' char(f)],'x(0)=1','Dx(0)=0')

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