I need to map a binary array to 2 differnet values corresponding to 0 & 1
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
A= zeros(320,320); A(60:180,60:180)=1;
lets say I wanna make all 1's = 2+3i and all 0's equals to 8-4i.
What would be the syntax to map them to corresponding values. Thanks
0 Commenti
Risposta accettata
dpb
il 29 Giu 2018
Modificato: dpb
il 30 Giu 2018
One of a zillion ways...
C=complex(2*ones(size(A)),3*ones(size(A)));
C(C==0) = 8-4i;
Another less "deadahead" but one-liner...
C=interp1([0 1],[8-4i 2+3i],A,'nearest');
ADDENDUM
A variation on the latter is simple lookup...requires the temporary vector, though.
v=[8-4i 2+3i]; % the values
C=v(A+1); % convert logical to array indices
0 Commenti
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Data Type Conversion in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!