How to find the total number of elements in individual row of a cell array?

C = {[1; 2; 3]; [2; 1; 3, 4]; [3; 1; 2]; [1; 2]}; 

Here,

in first row, elements are 1,2,3,1 | total number of elements = 4

in second row, elements are 2,1,1,2 | total number of elements = 4

in third row, elements are 3,3,2 | total number of elements = 3

in fourth row, elements are 4 | total number of elements = 1

% I was trying this code
sum = 0;
for i = 1:4
    C{i,1}(1); 
    sum = sum + 1;
end
sum % it gives me the output: total number of elements in row 1 which is 4.

% but error occurs when I write

sum = 0;
for i = 1:4
    C{i,1}(3); % row 3
    sum = sum + 1;
end
sum % it gives error

% Can you please help me to solve this issue?

[Bob Thompson]

What exactly is the error you are getting? And which line is producing it?

If all of your cells contain single column arrays then it might be easier to count based on the length of the arrays.

for i = 1:size(C,1);
    lngth(i) = length(C{i}) % Number of elements in each cell
end
for j = 1:max(lngth)
    row(j) = sum(lngth>=j); % Number of elements in each 'row'
end

[Md Shahidullah Kawsar]

Thanks.