How to remove a percentage of image counting from the bottom to top
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Stelios Fanourakis
il 30 Gen 2019
Commentato: Stelios Fanourakis
il 30 Gen 2019
Hi
I want to subtract a portion of image (e.g. 30% of it from the top). How do I do that?
If I do, something like this,
img = (croppedImage - (croppedImage.*0.3));
I usually get a 30% deduction from the bottom of it. I want this deduction to be from the top.
Moreover, I need a method to translate the deduction to number of rows. To be known, how many pixel rows this 30% of the image is.
Any ideas please?
1 Commento
Rik
il 30 Gen 2019
Do you want to change the size of your image, or the ensities that make up that image?
Risposta accettata
Mark Sherstan
il 30 Gen 2019
Modificato: Mark Sherstan
il 30 Gen 2019
Look at the example I wrote for you below. Use the size function and realize that imcrop takes an array in the form of [xPosition yPosition width height] where the (0,0) point is the top left corner of your image.
I = imread('test.png');
[height width dims] = size(I);
J = imcrop(I,[0 floor(height*0.3) width height-floor(height*0.3)]);
figure(1)
subplot(1,2,1); imshow(I)
subplot(1,2,2); imshow(J)
3 Commenti
Mark Sherstan
il 30 Gen 2019
Glad it worked! You could do something along the lines of this:
I = imread('test.png');
[height width dims] = size(I);
rows30 = floor(height*0.3) % I used floor but you can use ceil, round, etc...
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!