I need to classify my result in catagories

I have this in my code

N=ones(1,numel(ma)); 
% ma is a matrix can be given from other equations.
N(ma==45 | ma==135)=0.5;
N(0< ma<45 | 45<ma<90)=1.5;
N(0< ma<45 | 45<ma<90)=1.5;
N(90<ma<135 | 135<ma<180)=1.5;
N(ma==0 | ma==180)=0;
N(ma==90)=1;
NA=N';
NN=sum(NA(:));
Pn=ones(1,numel(NN));
Pn(NN>5)= 100000;
Pn(NN==5)=100000;
Pn(NN<5)=1;

I had the pervious fcn, but is doesn’t work.

The results as

ma=[-35.2644,0,0,-45.0000,-45.0000,0,35.2644,54.7356,30.0000,45.0000,0,-45.0000,30.0000,-54.7356,-54.7356,-54.7356,-35.2644]
N=[1.5000,0,0,1.5000,1.5000,0,1.5000,1.5000,1.5000,1.5000,0,1.5000,1.5000,1.5000,1.5000,1.5000,1.5000]

In other words I want to say:-

If ma=45 or 135 (with negative or positive signs) make N =0.5
If ma=0 or 180 , make N =0
If ma=90 or 275 (with negative or positive signs) make N =1
Otherwise make N= 1.5

Then Pn like that

If NN>or =5 make Pn=100000
If NN<5 Make Pn=1

Answer 1

[Star Strider]

Try this:

ma=[-35.2644,0,0,-45.0000,-45.0000,0,35.2644,54.7356,30.0000,45.0000,0,-45.0000,30.0000,-54.7356,-54.7356,-54.7356,-35.2644,NaN,90 275,180];
sdv = abs(sind(ma));
cls = 1.5*ones(size(sdv));                                       % Classification Vector
cls((sdv >= 0.69) & (sdv <= 0.72)) = 0.5;
cls(sdv > 0.9) = 1;
cls(sdv < 0.1) = 0;

To see the result:

Out = [ma; cls]                                                 % Result & Matching Inputs

Experiment to get the result you want.

[Mahmoud Sami]

It is work very good. Thanks for your help.

[Star Strider]

As always, my pleasure.

Answer 2

[dpb]

N=1.5*ones(size(ma));
N(abs(ma)==45 | abs(ma)==135)=-0.5;
...

The rest should be self-evident from the above; lett as "exercise for student" :)

Read sections on 'logical indexing' for how and why the above works but it is a most powerful Matlab coding idiom/syntax.

[Mahmoud Sami]

That's not working as i was thought.

The problem is that the result can't be as written in code.

I think there is something wrong

[dpb]

Works just fine here...

>> N=1.5*ones(size(ma))
N =
    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000    1.5000
>> N(abs(ma)==45 | abs(ma)==135)=-0.5
N =
    1.5000    1.5000    1.5000   -0.5000   -0.5000    1.5000    1.5000    1.5000    1.5000   -0.5000    1.5000   -0.5000    1.5000    1.5000    1.5000    1.5000    1.5000
>> [ma;N]
ans =
  -35.2644         0         0  -45.0000  -45.0000         0   35.2644   54.7356   30.0000   45.0000         0  -45.0000   30.0000  -54.7356  -54.7356  -54.7356  -35.2644
    1.5000    1.5000    1.5000   -0.5000   -0.5000    1.5000    1.5000    1.5000    1.5000   -0.5000    1.5000   -0.5000    1.5000    1.5000    1.5000    1.5000    1.5000
>> 

from which can see the substitution of -0.5 for the 45-deg positions...same will work for the other values as well...

Post your code and error messages...