list names in an array
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I have many files that i want to list their names in an array but the name is full for example
F:\New\checkfiles\C100.csv
5 Commenti
Barakat Ibrhim
il 13 Giu 2019
Adam Danz
il 13 Giu 2019
It sounds like you're doing something wrong.
Does your code look like this?
d = dir('C:\Users\name\Documents\MATLAB\');
% list all file
{d.name}'
the cyclist
il 13 Giu 2019
It would be handy if dir took an argument, allowing specification of the full path in the output. It seems like this would be a common enough thing to want to do.
Adam Danz
il 13 Giu 2019
Agreed. I suggested testing d.name because the OP stated that it was only returning file name when it should be returning the file extension as well.
Risposte (2)
Guillaume
il 13 Giu 2019
A lot simpler than all that has been suggested:
foldercontent = dir('C:\somewhere\*.csv');
filelist = fullfile({foldercontent.folder}, {foldercontent.name}); %that's all that is needed.
As said, if a string array is needed, string will convert the cell array of char vectors into a string array
4 Commenti
That is more simpler to read and more intuitive. However, for those obsessed with speed, The Cyclist's solution is 1.56x faster and my solution is 1.84x faster; probably due to avoiding overhead in fullfile (median speed comparison of 10,000 repetitions of each single line solution).
Guillaume
il 14 Giu 2019
I would argue that clarity completely trumps speed in this case particularly as the speed difference would be insignificant compared to the file IO that will inevitably follow.
Adam Danz
il 14 Giu 2019
Definitely clairity over milliseconds.
the cyclist
il 13 Giu 2019
I'm pretty sure there is a better, simpler way to do this, but I believe this does what you want:
s = dir;
fileList = cellfun(@(x,y)[x,'/',y],{s.folder}',{s.name}','UniformOutput',false);
4 Commenti
Barakat Ibrhim
il 13 Giu 2019
the cyclist
il 13 Giu 2019
Modificato: the cyclist
il 13 Giu 2019
string(fileList)
will convert the cell array to a string array (at least in R2018b).
Adam Danz
il 13 Giu 2019
"I'm pretty sure there is a better, simpler way..."
s = dir;
fileList = strcat({s.folder}',repmat({'/'},size(s)),{s.name}');
Stephen23
il 14 Giu 2019
"I'm pretty sure there is a better, simpler way..."
S = dir(...);
F = cellfun(@fullfile,{S.folder}',{S.name}','uni',0);
Or simply:
F = fullfile({S.folder},{S.name});
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