# How can I generate an array that keeps all the values related to specific indices keeps the zero as reference value?

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Seba.V on 21 Aug 2019
Answered: Ted Shultz on 21 Aug 2019
Given the array x=[ -2 -1 0 1 2 ] with respective array y=[2 1 3 5 4] and a value n=2
How can I generate a code that divides all the numbers of x by n, and generates a new array with only the values resulting from the division that are integers?
How can i then generate a new y array where only the values that were related to the (x/n = integers values) are included?
ie: if x=[ -2 -1 0 1 2 ], y=[2 1 3 5 4] and n=2
new_x=[ -1 0 1 ], new_y= [ 2 3 4 ]
or if
x=[ -3 -2 -1 0 1 2 3 ], y=[7 2 1 3 5 4 6] and n=3
new_x=[ -1 0 1 ], new_y= [ 7 3 6]
I hope it makes sense!

Ted Shultz on 21 Aug 2019
The following code does what you want for the values you gave as examples
hope this helps,
--ted
y=[2 1 3 5 4]
x=[ -2 -1 0 1 2 ]
n=2
tempX=x/n; % find x/n
keepIndex = tempX==floor(tempX); % find locations where these are integers
newX= tempX(keepIndex) % only keep values at those locations
newY=y(keepIndex)% only keep values at those locations