can someone tell what is happening in here are we assigning values to an array or what?

out1(nx,:,1)=[nx x1(i,1,1) y(i,1,1)];

nx=nx+1;

Answer 1

[Thiago Henrique Gomes Lobato]

In this case you are assigning a row vector to a row in matrix out1. One way to visualize this is using a very simple example:

First create a matrix and check the output

out1 = zeros(3,3,2);
x1 = ones(3,3,2);
y = ones(3,3,2)*2;
out1
out1(:,:,1) =

     0     0     0
     0     0     0
     0     0     0


out1(:,:,2) =

     0     0     0
     0     0     0
     0     0     0

Then do the assignment and check again the result:

nx = 3;
i = 1;
out1(nx,:,1)=[nx  x1(i,1,1) y(i,1,1)]; %[3 1 2]
out1
out1(:,:,1) =

     0     0     0
     0     0     0
     3     1     2


out1(:,:,2) =

     0     0     0
     0     0     0
     0     0     0
     

here you can cleary see the assigment of a row array to a row of the matrix.

Answer 2

[KALYAN ACHARJYA]

Is there any issue? I think no?

nx=nx+1; % nx updated with 1 and replace the present nx value

Following is the assigning out1 3D array

out1(nx,:,1);

Requested you to read this documentation, you will get sufficients hints to understand it.

Any specific issue, let me know here.