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How to export Excel files to the specific folder?

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I have the below code:
for p = 1:numel(C)
filename = C{p}{1,2};
if ~isempty(filename{:})
sprintf('%s.xlsx',filename{:})
writetable(C{p},sprintf('%s.xlsx',filename{:}))
end
end
I want to save all excel files generated in this code to "E:\AZAR\xlsx files 1989-2018" instead of the current folder. does anyone have an idea for how to do it?
Thank you all.

Risposta accettata

Adam Danz
Adam Danz il 15 Gen 2020
Use the fullPath = fullfile(path, filename) function to create full paths to files. This offers a number of very important benefits over simply concatenating strings to produce a full path. From the documentation,
  • fullfile inserts platform-dependent file separators where necessary (on Windows platforms it's a backslash \).
  • and it replaces all forward slashes (/) with backslashes (\) on Windows.
  • It also smartly concatenates string by collapsing inner repeated file separators.
directory = 'E:\AZAR\xlsx files 1989-2018';
filename = 'data.xlsx';
writetable(C{p},fullfile(directory,filename));
  6 Commenti
BN
BN il 15 Gen 2020
oh, it's done. really appreciate. I edited it and it's worked well.
out_dir='E:\AZAR\Prepared xlsx files 1989-2018';
for k = 1:numel(C)
filename = C{k}{1,2};
if ~isempty(filename{:})
baseFileName = sprintf('%s.xlsx',filename{:});
fullFileName = fullfile(out_dir, baseFileName);
writetable(C{k},fullfile(out_dir, baseFileName))
end
end
Thank you for your time and help :)
Adam Danz
Adam Danz il 15 Gen 2020
No problem!
Note the small improvement made below ( see arrow).
out_dir='E:\AZAR\Prepared xlsx files 1989-2018';
for k = 1:numel(C)
filename = C{k}{1,2};
if ~isempty(filename{:})
baseFileName = sprintf('%s.xlsx',filename{:});
fullFileName = fullfile(out_dir, baseFileName);
writetable(C{k},fullFileName) %<--------------
end
end

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Più risposte (1)

Jakob B. Nielsen
Jakob B. Nielsen il 15 Gen 2020
You can find the answer in the documentation for the writetable function. You must simply format your filename to be E:\AZAR\xlsx files 1989-2018\yourname.xlsx, for example using the strcat function, like;
strcat('E:\AZAR\xlsx files 1989-2018',sprintf('%s.xlsx',filename{:})));
  2 Commenti
BN
BN il 15 Gen 2020
Dear Jakob B. Nielsen
I tried this code that you wrote, but I don't know why it didn't work for me.
Thank you
Adam Danz
Adam Danz il 15 Gen 2020
It looks like the backslash may be missing between the path and filename.
Another possibility is that your platform expects a different path format.
These problems are all solved by using the fullfile() function.

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