Automatic cropping

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Jack
Jack on 8 Apr 2011
Answered: Samreen kayani on 9 Jan 2019
I have a cbir system and the output results depends on the cropping of the query image boundary and has to be the same as the cropping of the image boundary in the database. so i was wondering is there a way to crop an image automatically. e.g i do edge detection which gives outlines of the image. i want to crop a certain part of the image automatically. image is a numberplate i want automatic cropping of the image to only include the characters of the number plate and not any other extra little characters unless necessary if the letters mix in with the tiny characters.
an example would be good.
i.e.
this is the start of my code
a=imread(numberplate.jpg);
gr=rgb2gray(a);
bw=im2bw(gr);
edge=edge(bw,'canny',[0.15, 0.3])
crp=imcrop(edge)
This is manual i need automatic.
thanks
  2 Comments
Mohammad Bhat
Mohammad Bhat on 11 Mar 2018
HOW

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Answers (15)

Jack
Jack on 18 Apr 2011
i did read it, the explanation is only a few lines saying boundbox gives coordinates of xmin ymin and xwidth ywidth.
thats it
here is what i have tried
e=edge(a,'canny',[0.15,0.3]); reg=regionprops(e,'BoundingBox');
reg= 43x1 struct
so i know it has found 43 different bounding coordinates.
i then did reg.BoundingBox
xmin=ceil(ans(1,1)); ymin=ceil(ans(1,2)); xwidth=(ans(1,1)+ans(1,3)); ywidth=(ans(1,2)+ans(1,4));
i get a small area
then i tried after icropped=i(xmin,ymin,xwidth,ywidth) error=too many inputs
help would be appreciated thanks
  1 Comment
Walter Roberson
Walter Roberson on 18 Apr 2011
At your level of understanding, you should never name a structure followed by a field, only a structure followed by an index followed by a field. reg(K).BoundingBox for K from 1 to length(reg)
You might perhaps be wanting to find the bounding box that encloses all of the bounding boxes you found through edge detection; if so then you should be thinking about min() and max().
There _are_ some useful things you can do with naming a structure name and then a field name with no index, but your first order of duty is to get the code working; optimization can come afterwards.

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Walter Roberson
Walter Roberson on 8 Apr 2011
Do you have code now to detect the portion of the image which is the license plate?

Sean de Wolski
Sean de Wolski on 8 Apr 2011
Copy and paste that into a script||function and it'll be automatic.
  2 Comments
Sean de Wolski
Sean de Wolski on 8 Apr 2011
Very, true. But he said it works; it just isn't automated.

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Jack
Jack on 10 Apr 2011
Exactly it is not automated. the user has to do the cropping manually.
i want an automatic cropping without any user intervention of the boundary.
something like.
loop through the edge detected image where it is black value zero for the boundary around the image and use that as the crop boundary.

Sean de Wolski
Sean de Wolski on 11 Apr 2011
First off, don't overwrite the MATLAB function EDGE when you name the variable EDGE!
Could you just find the bounding box of the edge image using regionprops and extract it/save it etc? The rest is just manipulating the string for imread. You could do that with a variety of ways but you haven't made anything clear to us as to how what you want automated.
As Walter and I said before; assuming that your above code works (which we agreed it probably doesn't since numberplate.jpg should be in single quotes); everything else IS automated if you put it in a script and run it.

Wolfgang Schwanghart
Wolfgang Schwanghart on 11 Apr 2011
HTH, Wolfgang

Jack
Jack on 11 Apr 2011
firstly:i was rushing so i forgot the single quotes but that is not the problem.
Sorry for not explaining well
here it is.
input is numberplate image. i want to read it, convert it to gray scale. detect edges using canny method. crop it using imcrop. but the thing i need is the boundary around the image to use in the imcrop function so the user doesn't have to manualy crop the image.
these are the input images they need to be gray scaled and cropped to only include the letters and numbers only minimze any other lines interfering as seen on image 2. i want to find the boundary coordinates to crop.
i hope you understand what i want to crop. my code does work but that only tells the user to manually crop the image i want the cropping process to be automatic
i will try regionprops

Jack
Jack on 13 Apr 2011
i tried using region props but i don't understand how i would get the boundary of interest from the numberplate using regionprops. please help in explaining how to get the boundary coordinates around the number plate.
  2 Comments
LAXMI NARAYAN SONI
LAXMI NARAYAN SONI on 7 May 2017
Yes this is the right way.... U also have to be use a loop.

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Jack
Jack on 14 Apr 2011
im really confused i don't understand.
with bounding box i get a lot of coordinates.
i do something like a=regionprops(image);
reg=a.boundingbox;
this results in more than one answer.
is there an example or demo on the regionprops thanks
  1 Comment
Sean de Wolski
Sean de Wolski on 14 Apr 2011
That will give the coordinates for the boundingbox of each object. Read the documentation!!

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Jack
Jack on 20 Apr 2011
i did a loop to try and crop the image using all the coordinates from boundingbox.
i wrote
for i=1:length(reg) %in this case length of reg is 43
xmin=reg(k).BoundingBox(1);
ymin=reg(k).BoundingBox(2);
xwidth=reg(k).BoundingBox(3);
ywidth=reg(k).BoundingBox(4);
cr=imcrop(e,'canny',[0.15,0.3]);
imshow(cr);
end
for image 1 when k=4 the whole numberplate was captured including the borders and for image 2 it was when k=3 is it possible to get only the characters not the whole numberplate with the little flag if not i guess it is ok how do i stop the loop when i get that numberplate image boundingbox
note: ceil() the first two entries as the minimum x,y and then add the the third and fourth to the first and second respectively to get the maximum. Extract with: Icropped = I(ymin:ymax,xmin:xmax,:);
do i do ceil of BoundingBox(1)and(2) for x and y min get x and y max by adding BoundingBox(1) to (3) and (2) to (4) respectively
then icrop=i(ymin:ymax,xmin:xmax,:);
is this what was meant by that statement
thanks
  1 Comment
Sean de Wolski
Sean de Wolski on 20 Apr 2011
Assuming that BoundingBox is 1x4 (i.e. it was a 2d image) then this looks correct to me. What results did you attain? Did it work?

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priya
priya on 20 Apr 2011
I guess this should work... (not sure though). when you do imcrop() you should be able to right click and get the co-ordinates of the image which you have selected for croping.
%ime1 = findimage();
a=imread(numberplate.jpg);
gr=rgb2gray(ime1);
% BW=im2bw(gr);
edit=edge(gr,'canny',[0.15, 0.3])
im1 = imcrop(edit,[100.5 101.5 456 87]); imshow(im1);

Jack
Jack on 22 Apr 2011
but i don't want the user to do any work besides loading image the cropping should be automatic. can someone help. regarding my previous post.
thanks
  1 Comment
Jack
Jack on 22 Apr 2011
why is the thread not sorted in order of days answered. second from last post was posted 14 days ago or something. and the second post was posted a few days ago

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Jack
Jack on 22 Apr 2011
i tried what you said
when i reach up to reg=regionprops('BoundingBox')
you said to ceil the first two entries i ddn't know which of the 52 coordinates do i look at.
im guessing its is the bound that captures the whole numberplate. through the loop i said.
but when i ceil(first 2 entries i.e. xmin, ymin) then add entries 1 and 2 to 3 and 4 respectively after the ceil func.
its ok up this point but when i do icrop=i(ymin:ymax,xmin:max,:) it says index esceeds matrix dimension or something. if i do Capital I(ymin:ymax,xmin:xmax,:) says undefine function or variable I
i need help with this thanks

LAXMI NARAYAN SONI
LAXMI NARAYAN SONI on 7 May 2017
Edited: Walter Roberson on 14 May 2017
if u have a yellow color no. plate then u can use color based cropping... ike u can crop only yellow color. as simple as that.
clc
clear all
close all
a = imread('car3.jpg');
%b=imshow(a)
red = a(:,:,1);
green = a(:,:,2);
blue = a(:,:,3);
figure,imshow(red);
figure,imshow(green);
figure,imshow(blue);
%d = impixel(a);
i=size(a)
for c=0:i
if a(:,:,1)>13 or <255
if a(:,:,2)>0 or <201
if a(:,:,3)>0 or <104
d = imcrop(a);
figure,imshow(d)
end
end
end
end
  1 Comment
Sam Rosh
Sam Rosh on 7 Dec 2018
Edited: Sam Rosh on 7 Dec 2018
Jack Did you got the answer for finding only the interested bounding box? if yes can you share the code for the learneres like me.

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Samreen kayani
Samreen kayani on 9 Jan 2019
i want to segment each letter individually but bounding box divid 1 into 11 instead of 1.12 my answere is 11.112

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