plotting graphs in matlab

Hello

If i had the following

clear
clc
x=0:10
y=-2*x+6
y1=3*x

plot(x,y)
hold on 
plot(x,y1)

how would i just plot the graph with the limits being the x and y intercept

[Geoff Hayes]

Elliot - plaese clarify what you mean by with the limits being the x and y intercept. What do you want the minimum and maximum limits for the x and y axes?

[Elliott Cameron]

i want the plot to show no lower than where y1 intercepts the x axis and no higher than where y1 intercepts the y axis sorry i realise that wasnt very clear

[Star Strider]

Note that ‘y1’ intercepts both the x and y axes at (0,0).

[Elliott Cameron]

sorry y and y1 are the wrong way round

[Tommy]

You can solve for the intercepts using the equation for y1 and update the axes limits accordingly:

clear
clc
x=0:10;
y1=-2*x+6;
y=3*x;
plot(x,y)
hold on 
plot(x,y1)

yint = 6; % -2*0 + 6 => 6
xint = 3; % (0 - 6)/(-2) => 3
ax = gca;
ax.XLim(2) = xint;
ax.YLim(2) = yint;

[dpb]

@Tommy...you have/are developing my habit of putting Answers in Comments... :)

[Tommy]

Ah! Yes I agree... I do often question if I really understand what's being asked, and whether my "answer" is a full answer, but too often I default to the comment section

Answer 1

[Tommy]

You can solve for the intercepts using the equation for y1 and update the axes limits accordingly:

clear
clc
x=0:10;
y1=-2*x+6;
y=3*x;
plot(x,y)
hold on 
plot(x,y1)

yint = 6; % -2*0 + 6 => 6
xint = 3; % (0 - 6)/(-2) => 3
ax = gca;
ax.XLim(2) = xint;
ax.YLim(2) = yint;

[Elliott Cameron]

brilliant thats perfect, thank you