Converting binary to decimal and vice versa, please help!!
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
I'm having trouble converting strings that represent binary numbers to decimal and vice versa. The main issue is that I'm unsure of how to deal with the decimal point, say converting -11.11 to decimal. This is a homework assignment, so I'm not allowed to use the built in functions.
Here's my code for one of the two:
function decimal= mybin2real(binarystring)
decimal = 0;
for i = 1 : length(binarystring)
decimal = decimal + str2num(binarystring(i)) * 2^(length(binarystring) - i);
end
decimal
end
I was thinking about finding where the decimal point was using strfind, but i'm not sure how to implement it in the matlab code.
6 Commenti
Daniel Shub
il 2 Nov 2012
At the command line type
type bin2dec
or
edit bin2dec
this will let you see the source code.
Risposta accettata
Matt Fig
il 2 Nov 2012
Modificato: Matt Fig
il 2 Nov 2012
Here I have simply fixed your code. You were really close!
function decimal= mybin2real(binarystring)
% Converts an input string of 1s and 0s to a number.
Ind = strfind(binarystring, '.');
L = length(binarystring);
if isempty(Ind)
Ind = L+1;
end
Num1 = binarystring(1:Ind-1);
LN1 = length(Num1);
Num2 = binarystring(Ind+1:end);
LN2 = length(Num1);
dec1=0;
for ii = 1 : LN1
dec1 = dec1 + str2double(Num1(LN1-ii+1)) * 2^(ii-1);
end
dec2=0;
for ii = 1 : length(Num2)
dec2 = dec2 + str2double(Num2(ii)) * 2^-(ii);
end
decimal=dec1+dec2;
6 Commenti
Matt Fig
il 2 Nov 2012
No. As the very first thing....
if binarystring(1)=='-'
binarystring = binarystring(2:end);
F = -1;
else
F = 1;
end
Then at the end:
decimal = decimal*F;
Più risposte (2)
Andrei Bobrov
il 2 Nov 2012
Modificato: Andrei Bobrov
il 3 Nov 2012
decimal = (binarystring-'0')*pow2(size(binarystring,2)-1:-1:0).';
ADD
binarystring = '-11.11';
b = binarystring - '0';
[~,s] = ismember([-3,-2],b);
p = b(b >= 0);
decimal = sign(b(1))*p*pow2(diff(s) + (-2:-1:-1-numel(p)))';
prince kumar
il 15 Lug 2018
Modificato: KSSV
il 23 Ott 2019
n=input('input binary no.=');
n=int2str(n); s=0;
for i=1:numel(n)
s=s+(str2num(n(i))*(2.^(numel(n)-i)));
end
s
0 Commenti
Vedere anche
Categorie
Scopri di più su String in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!