Azzera filtri
Azzera filtri

cannot fill table with chars?

21 visualizzazioni (ultimi 30 giorni)
Hi I am having a pile of issues with the table features in matlab.
I can't figure out how to put a char array into a char variable of a table. I've been reading the table help files but Il'm missing something :(
x=[1;2;3];
y=[4;5;6];
T=table(x,y)
T =
3×2 table
x y
_ _
1 4
2 5
3 6
>> T.words = repmat({''}, 3, 1);
>> T(1,'words') = 'poop';
The number of table variables in an assignment must match.
>> T(1,3) = 'poop';
The number of table variables in an assignment must match.
>> T{1,3} = 'poop';
The value on the right-hand side of the assignment has the wrong width. The assignment requires a value whose width is 1.
  2 Commenti
Stephen23
Stephen23 il 24 Mag 2020
Modificato: Stephen23 il 24 Mag 2020
"...but Il'm missing something "
It isn't a character array. You defined it as a cell array of empty character vectors:
T.words = repmat({''}, 3, 1);
It is certainly possible to define words to be a character array:
>> T.words = char(nan(3,0))
T =
x y words
_ _ _____
1 4
2 5
3 6
>> T.words(1,1:4) = 'boat'
T =
x y words
_ _ _____
1 4 boat
2 5
3 6
>> size(T.words)
ans =
3 4
but that is likely to be useful only in some specific circumstances. I would imagine that most users would prefer a string array.
Giuseppe Degan Di Dieco
Giuseppe Degan Di Dieco il 12 Mag 2021
Dear Stephen,
thanks for your tip, indeed the solution of using a string array is very good.
Best.

Accedi per commentare.

Risposta accettata

Tommy
Tommy il 24 Mag 2020
x=[1;2;3];
y=[4;5;6];
T=table(x,y);
T.words = repmat({''}, 3, 1); % this creates a 3x1 cell array
After these lines, T.words is a cell array:
>> T.words
ans =
3×1 cell array
{0×0 char}
{0×0 char}
{0×0 char}
You can fill it like so:
T(1,'words') = {'a'};
T(2,3) = {'bcd'};
T{3,3} = {'e':'z'};
% alternatively,
T{3,3}{1} = 'e':'z';
Which results in this:
>> T
T =
3×3 table
x y words
_ _ ________________________
1 4 'a'
2 5 'bcd'
3 6 'efghijklmnopqrstuvwxyz'
  1 Commento
Giuseppe Degan Di Dieco
Giuseppe Degan Di Dieco il 12 Mag 2021
Dear Tommy,
thanks for your suggestion, it really made me understanding the repmat function.
It helped me in changing the content of a data table, it was a cell array but I defined the substitute as a string.
Best.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Matrices and Arrays in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by