How to remove for-loop in computing a vector of sums?
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How to compute rcross vector without the for-loop?
rcross = zeros( length(elementProduct) - prefixLen , 1 );
for ii = 1: length(elementProduct) - prefixLen
rcross(ii) = sum( elementProduct(ii : ii + prefixLen - 1) );
end
In one scenario prefixLen is 8. length(elementProduct) can vary from a few hundred to a few million.
6 Commenti
Paul Hoffrichter
il 8 Dic 2020
@KSSV,
Thank you for your comment. If you move it to an answer, I will accept it. Thanks again!
~Paul
Paul Hoffrichter
il 8 Dic 2020
I think your approach will also work. But I believe (without testing) that using conv would be slower than movsum.
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