how to find value of variable in natural logarithmic

How to find value of X:

ln(X/0.466)*66.66+X*4.4805*10^(-4)+X=5.66

[Jonas]

i think you have to solve this numerically.

[ibrahim alzoubi]

you mean manually

[Star Strider]

I would use fsolve, since it would appear to have at most only one root.

Remember to use log, not ln in your code.

[Scott MacKenzie]

hint #1: e^(ln(x)) = x

hint #2: e^(ln(y) + ln(z)) = y * z

Answer 1

[DGM]

This can be done a number of ways. It's a log plus a positive linear function of x. There will be only one solution. That makes everything easier.

% solving symbolically
syms X
eqn = log(X/0.466)*66.66+X*4.4805*10^(-4)+X==5.66;
aaa = double(solve(eqn,X))

% or using fsolve
f = @(x) log(x/0.466)*66.66 + x*4.4805*10^(-4) + x - 5.66;
bbb = fsolve(f,1)

% or using fzero
ccc = fzero(f,1)

% do the answers make sense? check it graphically
x = linspace(0.2,1,100);
y = log(x/0.466)*66.66 + x*4.4805*10^(-4) + x;
plot(x,y); hold on
plot([0.2 1],[1 1]*5.66)
plot(aaa,5.66,'bo')
plot(bbb,5.66,'ko','markersize',10)

[ibrahim alzoubi]

does the value of X is 0.5035?