How to replace cell values with consecutive values related to their index
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
For example:
a = 1x3 cell array
columns 1 through 3
{1x1} {1x5} {1x3}
I'd like to be able to replace the values in each cell array with consecutive values so that:
a = 1x3 cell array
{[1]} {[2 3 4 5 6]} {[7 8 9]}
Thanks!
0 Commenti
Risposta accettata
dpb
il 29 Mag 2021
c=[{cell(1,1)} {cell(1,5)} {cell(1,3)}]; % original cell array
% engine
n=cellfun(@numel,c);
v=1:sum(n);
i1=1;
for i=1:numel(n)
i2=i1+n(i)-1;
c{i}=v(i1:i2);i1=i2+1;
end
results in
>> c
c =
1×3 cell array
{[1]} {1×5 double} {1×3 double}
>> c{:}
ans =
1
ans =
2 3 4 5 6
ans =
7 8 9
>>
There's probably a clever accumarray() or arrayfun() syntax to avoid the explicit loop, but nothing came to me quickly...
Più risposte (1)
Stephen23
il 29 Mag 2021
Modificato: Stephen23
il 29 Mag 2021
Simpler:
C = {cell(1,1),cell(1,5),cell(1,3)}
N = cellfun(@numel,C);
D = mat2cell(1:sum(N),1,N)
1 Commento
dpb
il 29 Mag 2021
That's what I intended, but kept muffing the mat2cell syntax...it's always thrown me for a loop for some reason -- rarely ever use it I guess is likely cause.
Vedere anche
Categorie
Scopri di più su Resizing and Reshaping Matrices in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!