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Changing the atan function so that it ranges from 0 to 2*pi

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I know that the matlab atan function returns values in the range of -pi/2 to pi/2. How do i change it so that it goes over the full range 0 to 2*pi?
My first attempt was using a while loop, but it was incorrect.
I need to write a function mfile to set the built-in matlab function atan in the range of 0 to 2*pi without using atan2. im new to matlab so im unsure of what to do.
Thank you
  2 Commenti
wenjun kou
wenjun kou il 8 Mar 2017
Modificato: wenjun kou il 8 Mar 2017
Although you don't want to use atan2, I thought I might just put this out there since atan2 returns a range between -pi to pi:
a = atan2(y, x);
a = a .* (a >= 0) + (a + 2 * pi) .* (a < 0);

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Risposta accettata

Daniel Svedbrand
Daniel Svedbrand il 14 Set 2018
Modificato: John D'Errico il 3 Ago 2023
Adding mod 2*pi to atan2 should work just fine
z = mod(atan2(y,x),2*pi);
  6 Commenti
Feruza Amirkulova
Feruza Amirkulova il 3 Ago 2023
Yes, mod(atan2(y,x),2*pi) worked and its gradients are the same as for (atan2(y,x)).

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Più risposte (4)

Walter Roberson
Walter Roberson il 12 Giu 2011
Use atan2() instead.
  5 Commenti
Paulo Silva
Paulo Silva il 12 Giu 2011
I didn't include that statement on purpose, when none of the others if statements are true the value of v is NaN, you could also do this:
if isnan(v)
error('Arguments must be different from zero')
KA il 12 Giu 2011
ok, did not know that, thanks again

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Paulo Silva
Paulo Silva il 12 Giu 2011
The Wikipedia got all explained, you just need to do the code, it's very simple.
function v=myatan(y,x)
if nargin==1 %just in case the user only gives the value of y myatan(y)
if x>0
if y>=0 & x<0
if y<0 & x<0
if y>0 & x==0
if y<0 & x==0
if v<0
  2 Commenti
Mehmet Can Türk
Mehmet Can Türk il 9 Apr 2022
Modificato: Mehmet Can Türk il 9 Apr 2022
I checked the Wikipedia link and tested the code. First of all, thank you so much for the contribution.
I wanted to convert atan2 function from Matlab into another environment which supports only atan function. So I deleted the if block and everything worked perfectly.

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Kent Leung
Kent Leung il 21 Mar 2018
Modificato: Kent Leung il 21 Mar 2018
Better late than never. (Also posting as a future reference to myself.) The function below accepts y & x as vectors in Matlab. Rather than using 'if' statements, the below might be faster if there is some parallelization implemented in the built-in index searching.
Note: I have a slight disagreement with the above for the x>0 & y<0 case, as well as the for x=0 & y<0 case. The code below gives 0 to 2pi.
function v=myatan(y,x)
%---returns an angle in radians between 0 and 2*pi for atan
v(x>0 & y>=0) = atan( y(x>0 & y>=0) ./ x(x>0 & y>=0) );
v(x>0 & y<0) = 2*pi+atan( y(x>0 & y<0) ./ x(x>0 & y<0) );
v(x<0 & y>=0) = pi+atan( y(x<0 & y>=0) ./ x(x<0 & y>=0) );
v(x<0 & y<0) = pi+atan( y(x<0 & y<0) ./ x(x<0 & y<0) );
v(x==0 & y>=0) = pi/2;
v(x==0 & y<0) = 3/2*pi;

theodore panagos
theodore panagos il 27 Ott 2018
You can use the formula:
atan(x,y)=pi-pi/2*(1+sgn(x))*(1-sgn(y^2))-pi/4*(2+sgn(x))*sgn(y) -sgn(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))
x=x2-x1 and y=y2-y1
  1 Commento
theodore panagos
theodore panagos il 6 Ago 2023

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