Changing the atan function so that it ranges from 0 to 2*pi
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I know that the matlab atan function returns values in the range of -pi/2 to pi/2. How do i change it so that it goes over the full range 0 to 2*pi?
My first attempt was using a while loop, but it was incorrect.
I need to write a function mfile to set the built-in matlab function atan in the range of 0 to 2*pi without using atan2. im new to matlab so im unsure of what to do.
More Answers (5)
Paulo Silva on 12 Jun 2011
The Wikipedia got all explained, you just need to do the code, it's very simple.
if nargin==1 %just in case the user only gives the value of y myatan(y)
if y>=0 & x<0
if y<0 & x<0
if y>0 & x==0
if y<0 & x==0
Ali on 9 Jan 2015
Hi all, I actually want to regenerate the results presented in figure 10 (part b) and figure 11 (part b) of this paper: http://wwwrel.ph.utexas.edu/Public/Students/liwj/papers/paper1.pdf Can you please help me for the case of 0 to 3*pi (or generally n*pi), namely for the n-fold complex plane? this figure might be also helpful to elucidate my question: http://upload.wikimedia.org/wikipedia/commons/thumb/f/f6/Atan2Diagram.png/400px-Atan2Diagram.png Many thanks
Kent Leung on 21 Mar 2018
Edited: Kent Leung on 21 Mar 2018
Better late than never. (Also posting as a future reference to myself.) The function below accepts y & x as vectors in Matlab. Rather than using 'if' statements, the below might be faster if there is some parallelization implemented in the built-in index searching.
Note: I have a slight disagreement with the above for the x>0 & y<0 case, as well as the for x=0 & y<0 case. The code below gives 0 to 2pi.
%---returns an angle in radians between 0 and 2*pi for atan
v(x>0 & y>=0) = atan( y(x>0 & y>=0) ./ x(x>0 & y>=0) );
v(x>0 & y<0) = 2*pi+atan( y(x>0 & y<0) ./ x(x>0 & y<0) );
v(x<0 & y>=0) = pi+atan( y(x<0 & y>=0) ./ x(x<0 & y>=0) );
v(x<0 & y<0) = pi+atan( y(x<0 & y<0) ./ x(x<0 & y<0) );
v(x==0 & y>=0) = pi/2;
v(x==0 & y<0) = 3/2*pi;