Is there a function that retrieves the filename of the current script?

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Is there a way to, from a .m file, determine the filename (including directory path) of that .m file?

Risposta accettata

Walter Roberson
Walter Roberson il 20 Giu 2011
S = dbstack();
S(1).file
You might have to use the -completenames option.
  5 Commenti
Kevin  Hartman
Kevin Hartman il 13 Mar 2021
Additionally, S(1).name in the above example returns the filename sans extension c. MATLAB 2020b

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Più risposte (3)

Kaustubha Govind
Kaustubha Govind il 20 Giu 2011
p = mfilename('fullpath')
  3 Commenti
Walter Roberson
Walter Roberson il 20 Giu 2011
mfilename does not include the extension, and thus cannot distinguish between .p and .m files.
mfilename without any option does not include the path as was specifically requested by the user.

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Eric LePage
Eric LePage il 23 Ott 2019
I'd appreciate a qualification, because what I get for R2019b is not very helpful; it certainly isn't the name of the currently running mfile. Thanks.
P = mfilename
P =
'LiveEditorEvaluationHelperESectionEval67edf31d'
or
S = dbstack();
>> S(1).file
ans =
'LiveEditorEvaluationHelperESectionEval67edf31d.mlx'
  8 Commenti
Rik
Rik il 24 Ott 2022
@Chris Jennings You can strip the path away with the fileparts function:
[FullPath,Filename,ext]=fileparts(matlab.desktop.editor.getActiveFilename)

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Martin Koch
Martin Koch il 23 Ott 2022
With the Path class you can get the file path with
Path.this
and the parent directory with
Path.here
Use the string method to convert to a string if needed:
Path.this.string
Disclaimer: I'm the author.

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