photo

Birdman


Last seen: circa un mese fa Attivo dal 2017

Followers: 0   Following: 0

Messaggio

Someone who is interested in Mathematics, Control and Engineering. Also, music as a hobby.

Statistica

All
  • Revival Level 3
  • First Submission
  • 6 Month Streak
  • Guiding Light
  • Promoter
  • Solver
  • Knowledgeable Level 5
  • Thankful Level 3
  • First Answer

Visualizza badge

Feeds

Risposto
Plotting a discrete impulse in Simulink
Try the attached model. See if it works for you. You can modify it.

quasi 4 anni fa | 0

| accettato

Risposto
how to change a variable value in the middle of simulation in simulink
Try the attached model. Copy the structure and replace it with the pulse generation block. It should work. Instead of writing p ...

quasi 4 anni fa | 0

Risposto
How can I save and plot all values of x and y for each value of C? x and y values are in the vertical axis and C in the horizontal axis in the graphic. I need to use the function "solve"
Try the following code: clear;clc; V=[1 2 3 4]; A=3; for i=1:numel(V) C(i)=A*V(i); syms x y eqn1=C(i)*x+y==2;...

quasi 4 anni fa | 0

| accettato

Risposto
finding an equation of the tangent line to a curve at the given point in MATLAB
Actually, it is quite simple to do. For instance, let's define the equation symbolically in MATLAB: syms y(x) y(x)=4*x-3*x^2; ...

quasi 4 anni fa | 2

Risposto
Solving differential equations with Simulink
If you consider the ramp imput as a function r(t)=t; then the equation becomes If you code this in MATLAB: syms x(t) eq=...

quasi 4 anni fa | 0

| accettato

Risposto
External Mode Error in Simulink - Using TI Piccolo F2803x
The main thing about External Mode is that you need to make sure that the code is running on the hardware before you try to run ...

quasi 4 anni fa | 0

Risposto
Simulink stateflow condition for single pulse input
Try the attached model. Note how the inside of Stateflow is built.

quasi 4 anni fa | 0

| accettato

Risposto
Square approximation with a second degree polynomial, function determine.
Simply, you need to use Curve Fitting app for this purpose. Define your Xi and f(Xi) vectors in MATLAB workspace. Then open Curv...

quasi 4 anni fa | 1

| accettato

Risposto
How to have a implicit function of a symbolic variable in our expressions and calculations
Simply, you can define symbolic functions just like symbolic variables: syms x y z f(x) A=(3*x+5*y+3*z+5)*(f(x)+z); diff(A,x)...

quasi 4 anni fa | 0

| accettato

Risposto
How to Find Kp,Ki for PI controller from Gain and Time Constant value Given
Simply, the conversion is as follows(Let K denote gain and Ti denote time constant): K*(1+1/(Ti*s)) is equal to Kp+Ki/s If y...

quasi 4 anni fa | 2

| accettato

Risposto
computing a sequence of vectors
Try the following code: n=1;L=1;d=1;q=1;%randomly given syms alpha C=0.5*q*sin(alpha)*[L+d]; D=0.5*q*sin(alpha)*[L^2/d]; ...

quasi 4 anni fa | 0

| accettato

Risposto
How to analyze signal and make proper filter?
If you want to have a starting point, following code basically takes the psd of the signal, so that you will be able to obtain t...

quasi 4 anni fa | 0

Risposto
How to put max function in symbolic function
Why would you try to name it as max? Simply, piecewise function in Symbolic toolbox would help you: syms x f(x)=piecewise(x<0,...

quasi 4 anni fa | 1

Risposto
Receive Raw Ethernet Packet via Simulink
Solved.

oltre 4 anni fa | 0

| accettato

Domanda


Receive Raw Ethernet Packet via Simulink
Hello, My question is simple: I would like to use Simulink, just like Wireshark, to capture and display raw ethernet packets. I...

oltre 4 anni fa | 1 risposta | 0

1

risposta

Risposto
Derivate a function with two variable dependent of time
The following might help: syms r(t) theta(t) f(r,theta) f=r^2+0.2*cos(theta)-0.03 To take partial derivative, use functionalD...

oltre 4 anni fa | 0

Risposto
define tau in transfer function
The following might help: syms s t tau Cs=(1/s)*(1/(tau*s+1)); c(t,tau)=ilaplace(Cs) T=0:0.01:1; plot(T,c(T,0.1))

oltre 4 anni fa | 0

Domanda


Capabilities of Building Standalone Simulation Applications in App Designer with Simulink Compiler
Hello everyone, For those who do not know, MATLAB released Simulink Compiler with 20a release which helps to build and deploy s...

oltre 4 anni fa | 0 risposte | 0

0

risposte

Risposto
How is derivative made in Matlab ?
syms v(t) v(t)=t.^3-6t.^2+7; a(t)=diff(v); result=a(3.5)

oltre 4 anni fa | 0

| accettato

Risposto
Replacing characters in a string
One example(use regexprep): s="Yao Ming"; regexprep(s,{'Y','M'},{'J','Q'})

oltre 4 anni fa | 1

Risposto
How to update a variable in a function after every 5 seconds?
Run the attached model and see the results. You can change the Ramp block's Slope value and store different numbers. Output of t...

oltre 4 anni fa | 0

Risposto
Function like "find" but for lines
B=reshape(A.',1,[]); C=(1:numel(A)).*(B~=0); C=C(C~=0)

oltre 4 anni fa | 0

Risposto
Matrix with numeric values
N=4 A=1:N; B=char(64+A) 'ABCD' B(1) 'A' B(2) 'B' . . and so on. Change N and observe the results.

oltre 4 anni fa | 0

| accettato

Risposto
Solving non linear 2nd order differential equation
Try this: clear syms t Y0= input('wave amplitude ') ; %Wave ampli...

oltre 4 anni fa | 0

| accettato

Risposto
y[n] = x[n] - x[n-1] x[n-2] I need to find a) Find the transfer function. b) Give the impulse response. d) Sketch the frequency respo
Try this: z=tf('z',0.001); Gz=1-z^-1+z^-2; %%transfer function Gs=d2c(Gz,'tustin') %%impulse response figure(1); impulse(...

oltre 4 anni fa | 0

Risposto
How can I remove identical cell entries containing small arrays
The following code should simply do the job for you: unique(cell2mat(connect_group),'rows') After this, you can regroup the ar...

oltre 4 anni fa | 0

Risposto
Simulink-Sawtooth Decrease Counter
Try the attached model. Note that I didn't use Pulse Generator or Detect Decrease or Sum or Memory block. The model is very simp...

oltre 4 anni fa | 0

Risposto
how can I do this in mat lab
syms u(t) x(t) h(t) u(t)=piecewise(t>=0,1,0); x(t)=cos(pi*t)*(u(t)-u(t-1)); h(t)=1.5*(u(t)-u(t-1.5)); %%plot t=0:0.001:5; ...

oltre 4 anni fa | 0

| accettato

Risposto
Plotting the derivative of an "switch-funktion"
You may use Symbolic Toolbox and its beauties for this case :) Here is the code: syms y1(t) y2(t) y3(t) y4(t) y1(t)=piecewise(...

oltre 4 anni fa | 0

| accettato

Risposto
How can i fix the error 'Index exceeds the number of array elements (51)'
You need to apply elementwise division: x = [0:0.1:5]; y = sin(x)./x; plot(x, y), xlabel('xi'), ylabel('Theta'), title('Solut...

oltre 4 anni fa | 1

| accettato

Carica altro