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Matrix dimension does not agree when using .*

Asked by Sena Ece Uzungil on 1 Apr 2019
Latest activity Answered by Kelly Kearney
on 1 Apr 2019
Our code is calculating Taylor polynomials. We are sure that the problem is about P1 because program is plotting PO and f(x). We would really appreciate if anyone can solve our problem.
clc
clear all
close all
h = 0.01; % step size
X = -pi/8:h:7*pi/8; % domain
f=@(X) cot(X); % range
a=5*pi/8
Z1=@(X) diff(cot(X)) %first derivative
Z2=@(X) diff(cot(X),2) ; %second derivative
Z3=@(X) diff(cot(X),3) ; %third derivative
P0=@(X) f(a)*ones(size(X))
P1=@(X) f(a) + Z1(a).*(X-a);
P2=@(X) P1 + Z2(a) ./ factorial(2).*((X-a).^2);
P3=@(X) P2 + Z3(a) ./ factorial(3).*((X-a).^3);
xlim([0.1 3])
ylim([-2.5 2.5])
hold on
plot(X,f(X),'k','Linewidth',2)
plot(X,P0(X),'r','Linewidth',2)
plot(X,P1(X),'g-.','Linewidth',2)
plot(X,P2(X),'b--','Linewidth',2)
plot(X,P3(X),'m:','Linewidth',2)
The error we received:
Error using .*
Matrix dimensions must agree.
Error in Untitled>@(X)f(a)+Z1(a).*(X-a)
Error in Untitled (line 26)
plot(X,P1(X),'g-.','Linewidth',2)

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1 Answer

Answer by Kelly Kearney
on 1 Apr 2019
 Accepted Answer

When you calculate
Y = diff(X,n)
where X is a vector, Y will have length length(X)-n. So you need to adjust X accordingly when plotting, e.g.
plot(X,f(X),'k','Linewidth',2)
plot(X,P0(X),'r','Linewidth',2)
plot(X(1:end-1),P1(X),'g-.','Linewidth',2)
plot(X(1:end-2),P2(X),'b--','Linewidth',2)
plot(X(1:end-3),P3(X),'m:','Linewidth',2)

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