How do I compare each value and take the average of same number of every comparison in a vector?

I have a matrix A=[1124x1]. I want to check each element with the next element of the matrix A. If these elements are same then want the average value of them and result will be a matrix [Nx1] where N will be number of different element in the matrix A

for example A=[95; 95; 95; 96;96;96;97;97;97] and result will be [95;96;97].

Thank you

[Adam Danz]

"...result will be a matrix [Nx1] where N will be number of different element in the matrix A"

unique(A,'stable') 

But that is not the average of those groups. Is the unique() function what you were looking for?

If the input/output pattern below if your goal, see the following solution.

A=[95;95;95;96;96;96;97;97;97;95;95;96];  %input
B=[95;96;97;95;96];                       %output

idx = [true;diff(A)~=0]; 
B = A(idx); 

[the cyclist]

What should the output of

A = [95 95 96 96 97 97 95 95]

be?

Answer 1

[the cyclist]

Will identical values every be separated from each other? If not, then it seems like you just need

unique(A)

But this will not give you what you want if

A = [95 95 96 96 97 97 95 95]

Answer 2

[Dave]

In which case if A = [95 95 96 96 97 97 95 95], then you could just sort(A) and then apply unique.

[the cyclist]

Unless what he actually wants as ouput in this case is

A = [95 96 97 95]

[Adam Danz]

Then it would merely be

A([true,diff(A)~=0])