Azzera filtri
Azzera filtri

How to read a portion of file?

2 visualizzazioni (ultimi 30 giorni)
Chong Tao
Chong Tao il 15 Ott 2013
Commentato: dpb il 15 Ott 2013
I have a text file which contains 10 colomns, tab seperated floating numbers. Colomn 3 is the data for Length. it is formatted in ascending order. I hope to select only the portion of file within a certain length range. The code attached reads the whole file, stores them in an array and selects the portion in the range. Is there a way to read from file only the portions in range, not the whole file. Thanks.
WL_Low =1330; % Length range
WL_High = 1500;
fid = fopen('test.txt');%read in file
data = fscanf(fid,'%f',[10 inf]);% store to temporary data file
fclose(fid);
DT = data(:,data(3,:)>WL_Low & data(3,:)<WL_High)'; % select data in this range for processing.

Risposta accettata

dpb
dpb il 15 Ott 2013
Not nearly as efficiently as the above solution, no.
To do it on the fly while reading means processing each record one-at-a-time a much less efficient operation than operating on the file as a whole.
About the only exception to this could be if the file is so large as to cause memory problems or in that the file i/o is excessive. But, in the latter, it'll be even slower and the alternative there would be to go to stream instead of formatted file i/o.
  4 Commenti
Chong Tao
Chong Tao il 15 Ott 2013
thanks again dpb. this will work. is it possible to do what you suggested for large files, say if the file is 20 M bytes or larger, and keep my original code for small files?
dpb
dpb il 15 Ott 2013
Sure, w/ a little logic. You can inquire for the file the size via dir() and then set the size of the number of elements to read dynamically if above some threshold. The [M,N] values can be variables; they need not be constants.

Accedi per commentare.

Più risposte (0)

Tag

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by